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7.6

java script onChange

Asked by saad220 in JavaScript, Asynchronous Javascript and XML (AJAX), PHP Scripting Language

i have some php counter..

what i want is when dropdown list select...how could i display the search result on the page using ajax and onChange event???

i have the search function, count function...the only problem i faced is that...how could i manage to put them together with ajax to get the result live.

see example here if u want..

http://en.comparis.ch/Carfinder/marktplatz/result.aspx?marcode=0&origin=headline#AdjustSearch

please select price or car model u will see the count result update instantlly..how could i achieve that???...

some has idea please??

Get your answer NOW

         
           
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             search function..
 
function searchAll()
{
 
//base sql
  $sql = "select * from produkt_finder_table where 1 ";
 
//get the values from the form
//NOTE: You should do way more valdation on the values before you attempt to process anything
 
 
  if ((!empty($_POST['Bauform_d']))&&($_POST['Bauform_d'] != 'all'))
  {
    $sql .= " and Bauform_d like '". addslashes($_POST['Bauform_d'])."%' ";
  }
 
 
 
  //run query
  $result = conn($sql);
 
  if (!$result){ die("No results due to database error.<br>".mysql_error());  }
 
  if (mysql_num_rows($result)==0)
  {
    echo "No Results found!";
  }else{
 
    echo "<table border='1'><th>Cuenta</th><th>idclase</th><th>Enumber</th></tr>";
   
    while ($rows= mysql_fetch_array($result))
    {
      echo "<tr>";
	  echo "<td>";
	   echo "<ul>";
echo "<li class='addResult'><img src='{imag}' alt='' /><span class='red'>".$rows['Bauform_d']."<br /><span class='black'>".$rows['ArtikelName']."</span></span> <a href='#'>More Info</a> </li>";
echo "</ul>";
"</td>";
      /*echo "<td>". $rows['Bauform_d']  ."</td>";
      echo "<td>". $rows['Beschreibung_d'] ."</td>";
	  echo "<td>". $rows['ArtikelE_NO'] ."</td>";
      echo "</tr>";
      */
    } 
    echo "</table>";
  }//end if
 
 
 
}//end func
 
 
dropdown create function
 
function dropdown($field, $table)
{ 
  //initialize variables
  $oHTML  = '';
  $result = '';
 
  //check to see if the field is passed correctly
  if (($field == "")||($table == ""))
  {
    die("No column or table specified to create drop down from!");
  }
 
  $sql = "select distinct($field) from $table";
 
  //call the db function and run the query
  $result = conn($sql);
 
  //if no results are found to create a drop down return a textbox
  if ((!$result) ||(mysql_num_rows($result)==0))
  {
    $oHTML .= "<input type='text' name='$field' value='' size='15'>";
  }elseif (($result)&&(mysql_num_rows($result)>0)){
   
    //build the select box out of the results
    $oHTML .= "<select name='$field'>\n<option value='all' onChange='updateCount();'>All</option>\n";
    while ($rows = mysql_fetch_array($result))
    {
      $oHTML .= "<option value='".$rows[$field]."'>".$rows[$field]."</option>\n";
    }
    $oHTML .= "</select>\n";
  }
 
  //send the value back to the calling code
  return $oHTML;
}//end function
 
 
count function..
 
function countResult(){
 
 $sql2 = "select * from produkt_finder_table where 1 ";
 
  
 
  if ((!empty($_POST['Bauform_d']))&&($_POST['Bauform_d'] != 'all'))
  {
    $sql2 .= " and Bauform_d like '". addslashes($_POST['Bauform_d'])."%' ";
  }
  
  
 
  if ((!empty($_POST['Beschreibung_d']))&&($_POST['Beschreibung_d'] != 'all'))
  {
    $sql2 .= " and Beschreibung_d like '". addslashes($_POST['Beschreibung_d'])."%' ";
  }
 
$result = conn($sql2);
  //run query
 
  if (!$result){ die("No results due to database error.<br>".mysql_error());  }
 
  if (mysql_num_rows($result)==0)
  {
    echo "0";
  }else{
 
    echo mysql_num_rows($result);
}
}

           
         

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java script onChange

Asked by saad220 in JavaScript, Asynchronous Javascript and XML (AJAX), PHP Scripting Language

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