Question

How do I have different hidden divs shown/hidden by different buttons/checkboxes

Asked by: Mr-Madcowz

Hi,

I'm using the code (see code section) to show & hide a div on my form with a checkbox and it works well.

I would like to add extra divs to be shown/hidden by other checkboxes/buttons/links but no matter how I code it I can't get it to work.

I have got it working by adding this:

</script>
       <script type="text/javascript">
function moreinfo() {
$("#moreinfo").show(1500);
}
  </script>
  <script type="text/javascript">
function DemoRequest() {
$("#DemoRequest").show(1500);
}
  </script>

and then a few

<a href="#" onClick="moreinfo();return true">link text</a>

but this is a sloppy way to do it and I would like to keep it all within the one block of script.

Can anyone help me please.

thanks.


<script type="text/javascript" src="js/jquery.js"></script>
    <script type="text/javascript">
    $(document).ready(function(){
       
       $("#extra").css("display","none");
	   
        // Add onclick handler to checkbox w/id checkme
       $("#Ringback").click(function(){
       
        // If checked
        if ($("#Ringback").is(":checked"))
        {
            //show the hidden div
            $("#extra").show(1500);
        }
        else
        {     
            //otherwise, hide it
            $("#extra").hide(1500);
        }
      });
	  
    });
     </script>
 
 
Checkbox HTML:
 
<input name="Ringback" type="checkbox" id="Ringback" value="yes" class="select" tabindex="7" />

                                  
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Asked On
2009-03-10 at 05:53:19ID24215761
Tags

jquery

,

javascript

Topic

JavaScript

Participating Experts
2
Points
500
Comments
5

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Answers

 

by: brad2575Posted on 2009-03-10 at 06:11:29ID: 23846176

if you just want to show/hide one div at a time you can use a function like this and just pass it the div ID wherever you want to show/hide it.  This function will check what the div currently is hidden or displayed and just flip it to do the opposite.

call it like this:
showhide("divID")

function showhide(d) {            
      if (document.getElementById(d).style.display == "none"){
            document.getElementById(d).style.display = "";
      }else{      
            document.getElementById(d).style.display = "none";
      }
}

 

by: JohnSixkillerPosted on 2009-03-10 at 06:15:39ID: 23846214

Hi, if I understand you correctly:

<script type="text/javascript">
function show(id) {
  $("#"+id).show(1500);
}
</script>
 
<a href="#" onClick="show('moreinfo');">link text</a>
                                              
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by: Mr-MadcowzPosted on 2009-03-10 at 08:00:05ID: 23847476

Thanks for your replies.

I had trouble getting both of those  to work (don't ask me why) and in the end went for:

	function showhide(id) {
		 var state = document.getElementById(id).style.display;  
             if (state == 'block') {  
		$("#"+id).hide(1500);	 
                           } else {  
		$("#"+id).show(1500);
                           }  
		}
 
 
HTML:
<a href="#" onclick="showhide('moreinfo');">Link text.</a>

                                              
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by: JohnSixkillerPosted on 2009-03-12 at 06:50:12ID: 23868193

It's propably because of state (display property). If no is set it returns empty string. Also many other values can be used. INLINE for example.

Change condition to: if (state != 'none')

However for this simple task use jquery.toggle function:

function showhide(id) {
       $("#"+id).toggle(1500);
}

 

by: Mr-MadcowzPosted on 2009-03-17 at 09:04:17ID: 31556197

Thanks for your help guys.

20120131-EE-VQP-002

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