Your program compare the last 8 bits; if I want to compare the last 10 bits, how to do ?
Thanl you
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Ip addresses: Comparison (last 10, 12 or 14 bits)
Please,
I would want to compare 2 adresses in the same lan, for examples
$ip1 = "172.18.23.9";
$ip2 = "172.18.23.10";
we see here that $ip2 > $ip1, because 10 is greater than 9.
how to write a program in Perl which can make me to
take the last 10 bits(or let say x last bits in general ) and compare them ?
Thank you
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Answers
Here's an example.
$ip1 = '172.18.23.9';
$ip2 = '172.18.22.10';
@ip1_octets = split /\./, $ip1;
@ip2_octets = split /\./, $ip2;
$bits = 10;
$ip1_bin = unpack("b$bits", ($ip1_octets[2] . $ip1_octets[3]));
$ip2_bin = unpack("b$bits", ($ip2_octets[2] . $ip2_octets[3]));
print "ip1_bin: $ip1_bin\n";
print "ip2_bin: $ip2_bin\n";
if ($ip1_bin > $ip2_bin) {
print "$ip1 is greater than $ip2";
}
else {
print "$ip2 is greater than $ip1";
}
$x = 10;
$ip1 = "172.18.23.9";
$ip2 = "172.18.23.10";
$IP1 = unpack'N',pack'C*',split/\
$IP2 = unpack'N',pack'C*',split/\
$IP1 &= (1<<$x)-1;
$IP2 &= (1<<$x)-1;
if( $IP1 < $IP2 ){
print "$ip1:$x < $ip2:$x\n";
}elsif( $IP2< $IP1 ){
print "$ip2:$x < $ip1:$x\n";
}else{
print "$ip1:$x == $ip2:$x\n";
}
There's useful modules for doing IP comparisons as they can get very tricky.
#!/usr/bin/perl
use Net::IPv4Addr;
$ip1 = "172.18.23.9";
$ip2 = "172.18.23.10";
netmask="255.255.255.0"; # Adjust as required, or use CIDR notation
print "$ip1 is in the same network as $ip2\n" if ipv4_in_network($ip1,$netm
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by: HamdyHassanPosted on 2004-02-18 at 07:30:26ID: 10393299
Repeated question, please delete one of them
$ cat ip_parse.pl
#!/export/vol/bin/perl
$ip1 = "172.18.23.9";
$ip2 = "172.18.23.10";
$ip1 =~ s/\./:/g ;
$ip2 =~ s/\./:/g ;
($x1,$x2,$x3,$x4)=split(":
($y1,$y2,$y3,$y4)=split(":
print $x4." compare to ".$y4."\n";
if ( $y4 > $x4 ) { print $ip1." less than ".$ip2."\n"; } else { print $ip1." greater than ".$ip2."\n"; }
$ ip_parse.pl
9 compare to 10
172:18:23:9 less than 172:18:23:10