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01.11.2005 at 02:47AM PST, ID: 21269624
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8.6

what does ! -d $caneDir means? and why it's tru if this directory exists on the disc?

Asked by netformx in Perl Programming Language

Tags: , ,

Hi,

I habe code in Perl:
if ( ! -d $caneDir) {
print "1 caneDir"
            $ok = mkdir($caneDir, "w");
            if (! $ok) {
print "2"
                  print "Failed to create $tProject $!\n";
                  exit(1);
            }
      }

I put prints and see that caneDir="E:\Versions\... - and this directory exists on local machine (only case is different)!

so what  ! -d $caneDir checks?and  why I enter to where prints appear above and the message that is printed is: Failed to create No such file or directory
and whether mkdir is perl function or my defined function?

(sorry I have no idea in Perl)

thanksStart Free Trial
 
Keywords: what does ! -d $caneDir means? a…
Title
1 mkdir in win32
2 capture perl fail message
3 Designating filename only of script bein…
4 Newbie Perl syntax questions
5 Problems with mkdir()
6 mkdir
 
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[+][-]01.11.2005 at 03:23AM PST, ID: 13012273

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[+][-]01.11.2005 at 03:25AM PST, ID: 13012278

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About this solution

Zone: Perl Programming Language
Tags: canedir, mkdir, perl
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Solution Provided By: manav_mathur
Participating Experts: 3
Solution Grade: B
 
 
[+][-]01.11.2005 at 03:26AM PST, ID: 13012284

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[+][-]01.11.2005 at 03:40AM PST, ID: 13012356

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[+][-]01.11.2005 at 04:53AM PST, ID: 13012970

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[+][-]01.11.2005 at 08:35AM PST, ID: 13015374

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