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05.27.2006 at 07:35AM PDT, ID: 21866030
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9.2

Extracting a block of lines from a scalar

Asked by mjcoyne in Perl Programming Language

Tags: , ,

If the scalar $msg contains multiple lines of text (like the contents of an email message), how can I extract from it all lines between an opening token (say, Begin:) and the first blank line encountered?

I tried:

        my $quote .= $msg if /Begin:/ .. /^$/;

but it doesn't work -- in fact, I can't seem to get any variant of this to work, although the range operator seems as if it would be the way to go here.  I can do it this way:

       my ($quote) = $msg =~ /Begin:\s*(.*?)\n\s*\n/si;

but that seems rather inelegant.  Is there a better way?Start Free Trial
[+][-]05.27.2006 at 10:13AM PDT, ID: 16775992

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About this solution

Zone: Perl Programming Language
Tags: lines, extracting, text
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Solution Provided By: ozo
Participating Experts: 2
Solution Grade: A
 
 
[+][-]05.27.2006 at 11:40AM PDT, ID: 16776327

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[+][-]05.29.2006 at 06:54PM PDT, ID: 16786859

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[+][-]05.30.2006 at 01:01AM PDT, ID: 16788095

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