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12.29.2007 at 08:29AM PST, ID: 23048887 | Points: 250
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RegEx Memory Variables - Easy example BUT $1 not holding what I expected

Asked by lqwest in Perl Programming Language

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In the code below the $1 memory variable holds Samua (notice NO l )  instead of Samual? My question is why? I know HOW to fix the problem to get what I want, but want to learn WHY $1 does not hold what I expect.

The output  of the code snippet is:
Starting string $_ is: Samual Adams
$1 is:Samua $2 is:l Adams                           <------ my area of concern
$1 is:Samual $2 is:Adams              

From my book on the subject "The memory holds the part of the string matched by the part of the pattern inside the parenthesis". So inside the first parens I think it would find the entire first name 'Samual'?Start Free Trial 
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use strict;
$_ = "Samual Adams";
print "Starting string \$_ is: $_\n";
s{(\w+)(\w+)} {\$1 is:$1 \$2 is:$2}xms;       #area of concern
print "$_\n";
$_ = "Samual Adams";
s{(\w+)[ ](\w+)} {\$1 is:$1 \$2 is:$2}xms;
print "$_\n";
[+][-]12.29.2007 at 08:39AM PST, ID: 20548197

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[+][-]12.29.2007 at 11:30AM PST, ID: 20548677

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[+][-]12.29.2007 at 04:16PM PST, ID: 20549488

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[+][-]12.29.2007 at 04:35PM PST, ID: 20549523

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[+][-]12.29.2007 at 05:12PM PST, ID: 20549591

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[+][-]12.29.2007 at 07:10PM PST, ID: 20549770

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[+][-]12.29.2007 at 07:10PM PST, ID: 20549771

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[+][-]12.29.2007 at 07:12PM PST, ID: 20549776

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[+][-]12.30.2007 at 06:29PM PST, ID: 20553087

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[+][-]12.30.2007 at 07:54PM PST, ID: 20553264

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[+][-]12.30.2007 at 07:57PM PST, ID: 20553265

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