Loading a variable into a 4-dimensional array? : Perl

May 10, 2008 03:47pm pdt

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03.26.2008 at 01:24PM PDT, ID: 23271989

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9.4

Loading a variable into a 4-dimensional array?

Zone: Perl Programming Language

Tags: Perl

here's a variable I have that looks like this:

1 2 5 20
2 4 7 30
3 4 5 20
4 6 4 20

so the variable looks like this: 1\t2\t5\20\n2\t4\t7\30\n3\t4\t5\20\n4\t6\t4\20

How would I lode the var into a 4-dimensional array so it looks like:
@array[1,1] = 1
@array[1,2] = 2
@array[1,3] = 5
@array[1,4] = 20
@array[2,1] = 2
and so on?

Thanks,
MS

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Question Stats

Zone: Programming

Question Asked By: mschwade

Solution Provided By: Adam314

Participating Experts: 2

Solution Grade: A

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03.26.2008 at 01:37PM PDT, ID: 21215941

-dobbz-:

         
             #!perl
 
use Data::Dumper;
 
my $v = "1\t2\t5\t20\n2\t4\t7\t30\n3\t4\t5\t20\n4\t6\t4\t20";
 
my @a;
 
for (my $x = 0; $x <4; $x++) {
	my @temp = split(/\n/, $v);
	@a[$x] = split(/\n/,$temp[$x]);
 
}
 
print Dumper \@a;

Open in New Window

03.26.2008 at 01:43PM PDT, ID: 21215994

Rank: Genius

Adam314:

The way you are indexing the @array isn't right for perl, you would use $array[1][1]. Also, array indexes normally begin at 0, not 1.

If you really want the array to begin at 1 instead of 0, you coudl set $[=1, but this is highly discouraged.

Or you could fill the zero'th element with undef (or something else), so the first value from your data is at index 1.

Here is some code that will work though. I've added statements to allow your data to start at 1, but have them commented out.

         
           
           
             my @array;
#push @array, [];    #fill zero'th element with empty
while(<DATA>) {
	chomp;
	push @array, [split /\t/];     #Normal
	#push @array, [undef, split /\t/];     #Start at 1
}
 
 
 
__DATA__
1	2	5	20
2	4	7	30
3	4	5	20
4	6	4	20
           
         

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03.26.2008 at 01:46PM PDT, ID: 21216028

mschwade:

Wouldn't it be:

@a[$x] = split(/\t/,$temp[$x]);
instead of:
@a[$x] = split(/\n/,$temp[$x]);

??
Thanks,
MS

03.26.2008 at 01:55PM PDT, ID: 21216107

-dobbz-:

Depends on what you want to split on. \t splits on the Tab. \n splits on the NewLine. In my example I am splitting on the new line and loading that entire line into the Array.

03.26.2008 at 02:26PM PDT, ID: 21216377

Rank: Genius

Adam314:

That code from dobbz does not create a 2-dimensional array like you asked for. It creates an array, and loads a string (the entire line) into it. If you change it to /\t/ instead of /\n/, you will end up with just the first value of each line in your final array. Still not a 2-dimensional array.
Also, that is hard coded to have 4 rows of data. If this isn't always the case, that won't work.

If you have you data in a single variable, you can change the code I gave before to this to work with that:

         
             my $str = "1\t2\t5\t20\n2\t4\t7\t30\n3\t4\t5\t20\n4\t6\t4\t20";
 
my @array;
foreach (split(/\n/, $str)) {
	push @array, [split /\t/];
}

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Accepted Solution

03.27.2008 at 11:14AM PDT, ID: 21224284

mschwade:

Adam, how would I print these then? I tried this, but it didn;t work:
foreach (@array) {
print $_;
}

Thanks,
MS

03.27.2008 at 11:56AM PDT, ID: 21224653

Rank: Genius

Adam314:

         
             foreach (@array) {
    print join(", ", @$_) . "\n";
}

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03.27.2008 at 12:01PM PDT, ID: 21224692

mschwade:

one other question before i close this,

can I reference it this way:

print @array[1][1]; to get the value stored in 1,1?

Thanks!

03.27.2008 at 12:03PM PDT, ID: 21224708

mschwade:

I figured it out... print $array[1][1];

thanks!

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