Question

parsing into dir

Asked by: saibsk

I need to cd to a directory

/home/dven/docs

this directory contains subdirectories. IN this subdirectories i need to recursively look for a particular file called output.log.

IN the output.log i need to look for a particular line which match this 1=A.*2=B. Then I need to cat the file and retrieve that line. The values i the file are crtl A delimited.

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Asked On
2009-10-20 at 15:06:13ID24828745
Topics

Perl Programming Language

,

Unix Systems Programming

Participating Experts
3
Points
500
Comments
4

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Answers

 

by: ozoPosted on 2009-10-20 at 15:18:42ID: 25619237

perl -MFile::Find -e 'find(sub{if( $_ eq "output.log" ){ local($/,$\,@ARGV)=("\cA","\n",$_); /1=A.*2=B/ && print while <>}},"/home/dven/docs")'

 

by: saibskPosted on 2009-10-20 at 15:42:29ID: 25619384

if the record in the file is something like
1=A^A2=B
where it is ctrl A char
how do i pattern match that will something like this work I need to get 1 value

/"\cA"1=(.*?)"\cA"

 

by: vinit_kainPosted on 2009-10-21 at 03:25:40ID: 25622398



Try

cat `find ./ -type f -exec grep -l "1=A.*2=B" {} \;`|grep "1=A.*2=B"

Vinit

 

by: Adam314Posted on 2009-10-22 at 12:38:45ID: 25638125

You only want to print the (.*?) matching part, not the whole line?  Change what ozo gave to this:

perl -MFile::Find -e 'find(sub{return unless /^output\.log$/;local($/,$\,@ARGV)=(undef,"\n",$_); $_=<>; print "$1" while /"\cA1"=(.*?)"\cA"/g;},"/home/dven/docs")'

                                              
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