Question

How to create a folder using python

Asked by: ashok3sep

Hi all,


How could i create a folder using python if the folder name is provided by the user. and check if the folder already exists or not

regards,

Freedom

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Asked On
2005-06-07 at 07:08:56ID21449478
Tags

python

,

create

Topic

Python Scripting Language

Participating Experts
2
Points
50
Comments
3

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Answers

 

by: cjjcliffordPosted on 2005-06-07 at 07:15:49ID: 14162047

Use os.mkdir() to make tihe directory, os.path.exists() to see if the name exists, and os.path.isdir() to check if it is a directory...
>>> import os
>>> os.mkdir( '/tmp/mydir' )
>>> if os.path.exists( '/tmp/mkdir' ) and os.path.isdir( '/tmp/mydir' ):
...     print 'exists and is dir'
... else:
...     print 'does not exist or is not a directory!'
...
exists

 

by: hoffman_mmPosted on 2005-06-11 at 10:19:13ID: 14195760

You should note cjjclifford's code will throw an exception if the directory already exists. I would write it like this instead:

import errno
import os

DIRNAME = "/tmp/dir1/dir2/mydir"

try:
    # os.makedirs will also create all the parent directories
    os.makedirs(DIRNAME)
except OSError, err:
    if err.errno == errno.EEXIST:
        if os.path.isdir(DIRNAME):
            print "directory already exists"
        else:
            print "file already exists, but not a directory"
            raise # re-raise the exception
    else:
        raise

 

by: cjjcliffordPosted on 2005-06-13 at 00:40:05ID: 14200303

Hi,

My code was only an example of how to do the specific tasks, in the order they were asked in the question, not necessarily a real example :-)
Exactly what your program does if a directory already exists (either as a directory, or as another filesystem object) really depends on your requirements, e.g. if you want to create a new temporary directory for some persisted processing, that is going to be wipped at the end of the processing, re-using an existing directory might not be a good idea, as there may be some un-related files in there!)

BTW, I should have mentioned earlier, a more portable way of building directory/folder paths is to use the os.path.join() method - this takes 2 arguments (parent and child) and returns a correctly formatted path for the underlying OS - using this will reduce the need for OS specific code.

Cheers,
C.

20120131-EE-VQP-002

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