Just:
Main Topics
Browse All TopicsIn Django I have some template logic that I need to replicate inside python code.
Templater code
<a href="/link?id={{myObject.
I need to build that same url from inside python code. Problem is the string formatting doesn't work.
# Object definition
class MyObject(db.Model):
foo='bar'
#... later in code ...
myObj = MyObject("bar")
link = '<a href="/link?id=" + myObj.key + '> Link </a>'
How do I build the same link in python code that the django template would have given me?
This Question has been solved and asker verified All Experts Exchange premium technology solutions are available to subscription members.
Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.
If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.
Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.
Access the answers to your technology questions today.
30-day free trial. Register in 60 seconds.
Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Try it out and discover for yourself.
30-day free trial. Register in 60 seconds.
Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.
Business Accounts
Answer for Membership
by: ramromPosted on 2009-11-05 at 08:22:54ID: 25751058
'<a href="/link?id=" + myObj.key + '> Link </a>' is missing an '
'<a href="/link?id="' + myObj.key + '> Link </a>'
^
In the future, instead of saying "doesn't work" explain exactly. Did you get an error? or unexpected results?