Question

Deleting an unknown number of folders in c:\temp

Asked by: Simon336697

Hi guys hope you are all well.

Guys,

I have a list of machines in a file called comptuers.txt
What I need to do is to:
In their c:\temp folder,
Find all folders that start with ses and remove them, that is, the folder and all the contents inside it. There could potentially be 100s of these in the c:\temp folder.
Any help greatly appreciated.

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Asked On
2009-11-04 at 15:35:52ID24873002
Topic

Windows Batch Scripting

Participating Experts
6
Points
500
Comments
12

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Answers

 

by: jkratzerPosted on 2009-11-04 at 15:40:16ID: 25745394

Create a batch that will run at startup through GPO.
Batch code something liike this:

cd c:\temp
del ses*.* /f /s /q 
rmdir /s /q ses*.*

                                              
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Select allOpen in new window

 

by: samenglishPosted on 2009-11-04 at 16:06:59ID: 25745552

@jkratzer
That was too easy mate... way too easy. I think he wants you to cycle through each of the computer names in computers.txt and then do what you suggested inside the loop... (perhaps use a for loop). Have another go mate.

 

by: vahiidPosted on 2009-11-04 at 18:31:07ID: 25746266

This batch file will do it for you. Note that you need to have Full Admin rights on the computers listed in the text file and the firewall should be off on those machines.

This script will create a batch file called "DelAll.bat" which you have to run yourself. The reason for that is I didn't want to you run it without checking the 2nd batch file to make sure it is deleting what you want it to delete.

@echo off
setlocal EnableDelayedExpansion
echo @echo off >delall.bat
 
for /F "delims=," %%T IN (computers.txt) do (
 set cname=%%T
 
 for /f "tokens=*" %%i in ('dir /b /ad \\!cname!\c$\temp\ses*') do (echo rd /s /q \\!cname!\c$\temp\%%i >>delall.bat)
)
                                              
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Select allOpen in new window

 

by: t0t0Posted on 2009-11-05 at 01:58:59ID: 25747970

Please try the following batch file:



@echo off
for /f %%a in (computers.txt) do (
   for /f "tokens=*" %%b in ('dir /ad /b "\\%%a\c$\temp\ses*"') do (
      rmdir /s /q "\\%%a\c$\temp\%%b"
   )
)

 

by: t0t0Posted on 2009-11-05 at 02:04:31ID: 25747991

for a visual solution, please try the following:


@echo off
for /f %%a in (computers.txt) do (
   set /p .=%%a<nul
   for /f "tokens=*" %%b in ('dir /ad /b "\\%%a\c$\temp\ses*"') do (
      set /p .=.<nul
      rmdir /s /q "\\%%a\c$\temp\%%b"
   )
   echo.
)

 

by: t0t0Posted on 2009-11-05 at 02:07:01ID: 25748000

here's an extended version of the previous code (not the titlebar)

@echo off
for /f %%a in (computers.txt) do (
   set /p .=%%a<nul
   for /f "tokens=*" %%b in ('dir /ad /b "\\%%a\c$\temp\ses*"') do (
      title %%b
      set /p .=.<nul
      rmdir /s /q "\\%%a\c$\temp\%%b"
   )
   echo.
)

 

by: QlemoPosted on 2009-11-07 at 05:22:06ID: 25766217

I think is much better to remotely execute the rd command. E.g. with the famous psexec command (www.sysinternals.com, free):

psexec @computers.txt -n 5 -d cmd /c for /D ^%D in ^(c:\temp\ses*^) do rd /s /q ^%D

The -n 5 waits max. 5 seconds for the remote computer to respond, -d detaches psexec - it does not wait till the rd is executed.

 

by: Simon336697Posted on 2009-11-10 at 11:59:47ID: 25789133

Hi all you kind great gurus, thanks so much for your help on this :>)
vahiid, can I first ask you, what the ! exclamation marks do in your code?

 

by: QlemoPosted on 2009-11-10 at 12:07:41ID: 25789218

The exclamation mark is used for a feature called Delayed Expansion (switched on with setlocal EnableDelayedExpansion). It allows for variables to be changed in the same code block or line, and is replaced when executing.
A block is built by the parenthesis (). If you use

setlocal EnableDelayedExpansion
set x=0
for %%A in (1 2 3 4) do (
 set x=%%A
 echo %x%
 echo !x!
)
You will see the difference. The first echo will output 0 in each loop, while the second echo counts up.

Why? Because the whole part in () is parsed as a single line, and %x% is replaced when parsed, not executed. !x! is replaced when executed.

 

by: billprewPosted on 2009-11-10 at 12:09:23ID: 25789236

The ! works very much like the % for referencing variables.  The difference being that the % referenced variables are resolved one time when the statement containing them is read by the batch processor.  On the other hand, the ! referenced variables are resolved everytime that line of code is executed.

This all assumes that "setlocal EnableDelayedExpansion" has been specified, to enable this feature.

The way I think about it is the ! references are a bit more real time, so if a variable is set in any kind of a loop, the best way to reference is typically with the ! format.  This assures that the value you get is the updated value.

A little more info on this can be found in by doing "HELP SET" at the command line.

You may also find this link useful to better understand.

http://batcheero.blogspot.com/2007/06/how-to-enabledelayedexpansion.html

~bp

 

by: vahiidPosted on 2009-11-10 at 12:14:02ID: 25789282

It's because of the 2nd line: setlocal EnableDelayedExpansion

Normally batch files will expand environment variables once for each command/line. Also escaped characters (^) are evaluated just once. This can have undesirable side-effects when using commands which span multiple lines, like FOR and IF. Setting EnableDelayedExpansion will reverse this behavior.

But then instead of %variable% you will use !variable! in your script.

Vahid

 

by: t0t0Posted on 2009-11-10 at 13:21:10ID: 25789999

Simon336697

did neither of my solutions above answer your question?

20120131-EE-VQP-002

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