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08.06.2007 at 12:19AM PDT, ID: 22743509
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7.4

Reading dns info from UNIX shell script into variables for writing to simple text file

Asked by mass2612 in Shell Scripting, Unix Operating Systems, Unix Systems Programming

Tags: , , , ,

Hi all,

I am trying to write a quick UNIX shell script to execute a nslookup and then read the output to a simple file for easy editing. Basically I want the hostname, FQDN host name and IP address to output to the same line for each host in a text file. I've managed to get to the point where I can get the hostname and FQDN hostname outputting as required but I'm not sure how to get the IP address of the host and ignore the IP address of the DNS server.

Any help would be great here's what I have: -

for HOST in host01 host02 host03
do
HOST_DATA=`echo $HOST` ; HOST_DATA2=`nslookup $HOST | grep ${HOST} | awk '{print $2}'`
HOST_DATA3=`nslookup $HOST | grep Address: | awk '{print $2}'`
echo $HOST_DATA $HOST_DATA2 $HOST_DATA3
done

This is the result: -
host01 host01.domain.com 192.168.1.5 192.168.1.1
host02 host02.domain.com 192.168.1.5 192.168.1.2
host03 host03.domain.com 192.168.1.5 192.168.1.3

All I want is to be able to get the IP of each host on the corresponding line so I end up with: -
host01 host01.domain.com 192.168.1.1 # for example but greping for Address: also fives me the DNS server IP address 192.168.1.5 I want to ignore that one.

Thanks as always for your time and assistance.
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[+][-]08.06.2007 at 04:03AM PDT, ID: 19637340

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[+][-]08.06.2007 at 04:21AM PDT, ID: 19637448

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About this solution

Zones: Shell Scripting, Unix Operating Systems, Unix Systems Programming
Tags: shell, script, unix, file, variable
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Solution Provided By: ahoffmann
Participating Experts: 3
Solution Grade: A
 
 
[+][-]08.06.2007 at 04:24AM PDT, ID: 19637463

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[+][-]08.06.2007 at 09:57PM PDT, ID: 19643387

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[+][-]08.10.2007 at 09:46AM PDT, ID: 19671499

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[+][-]08.10.2007 at 10:33AM PDT, ID: 19671923

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