grep -v "Date" /path/to/listing | awk '{printf "%s \t%s\n", $5, $4}'
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Question
Unix Shell or MSDOS batch script to do vertical cut & paste of columns of data
Hi,
I have a listing of files in the following format (from MSDOS "dir" output):
03/15/2008 06:31 PM 25 100011.uuid
03/15/2008 06:31 PM 189,440 10001411.uuida
I would like a script to read the file to strip off the date & time columns &
reproduce a new file which only has 2 columns : filename followed by filesize.
Attached is a sample listing (the top few lines) and the desired output (bottom
few lines)
Can be a Unix Shell script or an MSDOS Batch script.
Note that the file is very huge, about 1.5Gb in size, so the script must be
able to read such a big file & not bombs out (as vi editor, MS Excel & MS Word
can't open the file)
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Answers
From Windows side.... 2 questions.
Can you re-run the dir output? If so can easily just produce name and size using a for command etc. but working on what you have from dos for completeness:
@echo off
setlocal enabledelayedexpansion
set outfile=outfile.txt
del %outfile% 2>NUL
for /f "tokens=4* delims= " %%a in (c:\filelist.txt) do set size=%%a& set size=!size:,=!&(echo !size!,%%b)>>%outfile%
You can re-arrange the final echo bit as needed. This sends size,filename at the mo. and the other bits before remove the commas in the size field.
for /f "tokens=4* delims= " %%a in (c:\filelist.txt) do (echo %%a %%b)>>%outfile%
would send it as you request specifically.
Steve
Thanks guys, the filenames do not have spaces in between, fortunately.
So these scripts (Unix & MSDOS) would not bomb out half way due to the
large input file size, right?
To clarify Dragon-it, codes, (yes, I want the filename first), so is the following codes correct :
(Note: I assume the codes below is reading filelist.txt & not reissuing "dir ..." command again, right?)
@echo off
setlocal enabledelayedexpansion
set outfile=outfile.txt
del %outfile% 2>NUL
for /f "tokens=4* delims= " %%a in (c:\filelist.txt) do set size=%%a& set size=!size:,=!&(echo %%b %%a)>>%outfile%
Or is there an MSDOS "dir/..." options that would just give me the filename & sizes
without other information (dir/b/
Correct. %%a is the first "token" on the line and %%b is the rest of the line. The "tokens=4*" bits means assign the 4th token to the variabl given (%%a) and the rest of the line (in case of spaces) to the next variable (%%b). This could have been then if there are no spaces: "tokens=4,5" or "tokens=4-5" or you could have used "tokens=1-5" and then %%a is the date, %%b the time, %%c is AM or PM, %%d is the size and %%e the filename...
Hope that doesn't confuse more!
You could do a
for /r %a in (c:\*.*) do echo %~na %~za
To get the filename and size (for /? for details) of all files in the dir (this from command line you replace each % with %% to put it in a batch file. This only works from NT4 upwards, not "proper" DOS or Windows 9x DOS so if you have a real DOS OS you can't do that, though of course if you have the drive in a newer OS you CAN.
Steve
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by: oheilPosted on 2009-10-12 at 05:40:10ID: 25550671
unix:
awk '{print $4,$5;}' your_file_name
or if you want to create the result in a new file:
awk '{print $4,$5;}' your_file_name > your_new_file
If you have spaces in the file names (last column in your file) this would be a problem with awk.
It would be best, if the columns would be tab separated. In this case the awk command looks like:
awk 'BEGIN{FS="\t";}{print $4,$5;}' your_file_name
Regards,
Oli