Question

Unix Shell Perl script to filter out repeated sort key within a large file ( sed awk grep wc )

Asked by: sunhux

I have following files (with millions of lines) which is currently not sorted
 by first column value & may have preceding space(s) in front :

113 found in platter 3222
127 found in platter 3922
  113 found in platter 3735
1323 found in platter 3213
 1323 found in platter 3898
53323 found in platter 3288
1323 found in platter 3223
....
 (127 & 53323 each occurs only once in this file)

The output should be (ie those records with first column value will
be eliminated & sorted by first column as primary key followed by
5th column value as secondary sort key) :

113 found in platter 3222
113 found in platter 3735
1323 found in platter 3213
1323 found in platter 3223
1323 found in platter 3898
....

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Asked On
2009-10-21 at 01:58:03ID24829801
Tags

Unix Shell Perl script to filter out repeated sort key within a large file ( sed awk grep wc )

Topics

Shell Scripting

,

Perl Programming Language

,

Unix Operating Systems

Participating Experts
3
Points
500
Comments
7

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Answers

 

by: sunhuxPosted on 2009-10-21 at 02:05:40ID: 25621934


To elaborate:

this is a search for repeated primary sort key within the same file itself

 

by: sunhuxPosted on 2009-10-21 at 02:06:59ID: 25621943


Correction :
> ... those records with first column value that occur once only will
>    be eliminated, retaining those with first column value that are repeated

 

by: arnoldPosted on 2009-10-21 at 02:25:39ID: 25622071

The snippet below will simply strip out the leading spaces and will sort.
Not sure what the significance is of the 127 and 53323 comment.
you can use the egrep -v '^(127|53323)' line added before or after the sort or after the cat <filename>

cat <filename> | sed -e 's/^\s*//g' |sort
or 
sed -e 's/^\s*//g' <filename> |sort

                                              
1:
2:
3:

Select allOpen in new window

 

by: KeremEPosted on 2009-10-21 at 02:26:43ID: 25622082

Hi,

I'm not good at PERL script unfortunately. But the solution I've prvided for the other question will work here too. Becasue AWK will not be fooled with the leading space. so the result will be something like this:

awk -F' ' '{ print $1 }' data1 |sort -n | uniq -d | fgrep -f - data1

113 found in platter 3222
  113 found in platter 3735
1323 found in platter 3213
 1323 found in platter 3898
1323 found in platter 3223

 

by: sunhuxPosted on 2009-10-21 at 23:11:34ID: 25631216

Hi Arnold

127 and 53323  are the primary sort keys for 2 of the lines in the file, so
lines with the unique (ie occurring once) first column value should be
stripped out or excluded in the output

Hi KeremE,

For some reason the code you gave worked with a sample file earlier
but this time for searching within the same file gave incorrect output :
think everything including the lines with unique first value column got
included in the output .... but I'll try to describe more precisely later

 

by: vinit_kainPosted on 2009-10-22 at 02:30:19ID: 25632168

I updated the previous solution with new requirement

Try this

sort -n YourFileName|awk '{ if((NR!=ONR)&&($1==Y)) { if(COUNT==0){print X;COUNT=1};print $0 } else {COUNT=0} ;X=$0;Y=$1;ONR=NR}'

Regards
Vinit

 

by: vinit_kainPosted on 2009-10-22 at 02:34:40ID: 25632197

to remove white charaters from start of line


sort -n YourFileName|awk '{ if((NR!=ONR)&&($1==Y)) { if(COUNT==0){print X;COUNT=1};print $0 } else {COUNT=0} ;X=$0;Y=$1;ONR=NR}' |sed "%s/^ *//"



Vinit



20120131-EE-VQP-002

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