Question

parsing decimal fields in flat file

Asked by: saibsk

I am getting a flat file which is pipe delimited. I am parsing the file using awk and insertng the value into a DB. But of the value os in decimal format which the column in the database is int

awk -F'|' {
Name=$1,
id=$2,
acc_qty=$3

printf ("update table set name = %s where id = %d, $1, $2)

}>out.sql

but the acc_qty is somethig like 100.0 I need to insert just 100 to the qty column in the db but it is in int format.

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Asked On
2009-11-03 at 11:46:39ID24868521
Topics

Shell Scripting

,

Unix Systems Programming

Participating Experts
2
Points
500
Comments
15

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Answers

 

by: woolmilkporcPosted on 2009-11-03 at 11:57:43ID: 25732869

not quite sure, but try

printf ("update table set name = %s where id = %.0f, $1, $2)

 

by: amit_gPosted on 2009-11-03 at 11:58:48ID: 25732885

printf("update table set acc_qty = %d where id = %d", $3, $2)

or

printf("update table set acc_qty = %s where id = %d", int($3), $2)

 

by: saibskPosted on 2009-11-03 at 13:01:13ID: 25733578

hi amit_g i tried u;'r first option but gives me an error
Arithmetic overflow during implicit conversion of BIGINT value '2961387000' to a
INT field .

 

by: amit_gPosted on 2009-11-03 at 13:14:56ID: 25733747

Use ld instead of d

printf("update table set acc_qty = %ld where id = %d", $3, $2)

 

by: amit_gPosted on 2009-11-03 at 13:16:54ID: 25733774

Oh, this error may be coming from the database not from awk. If so you need to change your table column to BIGINT instead of INT. The INT in SQL server can only store up to 2,147,483,647 and your number is bigger than that.

 

by: saibskPosted on 2009-11-03 at 13:59:56ID: 25734268

can u please tell me if the number if 10.0 and i want to get just 10 can i use gsub or something liek that

 

by: amit_gPosted on 2009-11-03 at 14:24:25ID: 25734493

The printf with %d or use of int($3) will do that. You don't need gsub for that.

echo "10.0" | awk '{printf("%d\n", $0)'}

echo "10.0" | awk '{printf("%s\n", int($0))'}

 

by: saibskPosted on 2009-11-03 at 15:11:54ID: 25734942

ok i need to make a change like this if the field has more than 8 digits
ie > 99999999.0 then i need to make the field's value as 99999999 Please advise this would solve the above problem

 

by: amit_gPosted on 2009-11-03 at 16:05:47ID: 25735260

It is same as making it an int so yes the same solution applies.

 

by: saibskPosted on 2009-11-03 at 16:11:03ID: 25735290

P1 = sprintf("%d\n",$9);
P@ = sprintf("%d\n",$11);
 if ( P1> 99999999 ){
                 P1= 9999999;
  }
  if ( P2 > 99999999 ){
  P2 = 999999;
     }

I did soemthing liek this but still bypasses the if loops and tried to insert into DB

 

by: amit_gPosted on 2009-11-03 at 16:38:56ID: 25735419

Show the complete code. The posted code doesn't show anything where the if condition would cause an skip in the DB statement. You should also add more debug statements to output the values like P1 and P2 to confirm that they get expected values.

 

by: saibskPosted on 2009-11-03 at 17:52:14ID: 25735734

can u just please tell me if i want to print the values of P1 and P2 above how can i do that?

 

by: amit_gPosted on 2009-11-03 at 19:08:40ID: 25736075

printf("P1 = %s, P2 = %s\n", P1, P2);

It would help us getting it resolved much quickly if more code is shown.

 

by: saibskPosted on 2009-11-04 at 05:00:13ID: 25738819

AKYI|ACCESSKEY|S|Sheets|Current Information|N|Common|Domestic|304751679.0|2008-01-23 00:00:00|365276388.0|2009-08-15 00:00:00|
cat test.txt| awk -F'|' '{
Num = sprintf("%d\n",$9);
#printf("Num = %d\n", Num);
if ( Num gt 999999 ){
  print 'OK';
}
}'

I am getting the ninth field never enters the if loop

 

by: amit_gPosted on 2009-11-04 at 08:08:18ID: 25740732

echo "AKYI|ACCESSKEY|S|Sheets|Current Information|N|Common|Domestic|304751679.0|2008-01-23 00:00:00|365276388.0|2009-08-15 00:00:00" | awk -F'|' '{
Num = sprintf("%d\n",$9);
Num = int(Num);
printf("Num = %d\n", Num);
if ( Num >= 999999 ){
  print "OK";
}
}'

20120131-EE-VQP-002

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