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08.28.2007 at 07:49AM PDT, ID: 22791648
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7.8

Bash scripting question - Creating a Loop and using a 'dynamic' variable

Asked by achirayil in Bourne-Again Shell (bash), Linux Programming, Scripting Languages

Tags:

Bash Script Question
I want to write a short clean script that will have just one main body doing all the work, but will parse through 70+ times using a loop. I want to set up variables (process1, proccess2, etc) that will be referenced by the main body of the script; cycling through another process each time. Currently my idea is setup a loop and find a way to tie the 'count' of the loop against a variable that will correctly populate the value of all those 'process' varriables. First am I approaching it the right way; second if not please provide sugestions and an example... . I will provide a bit more of a detailed example below:
Here's what I was thinking:

#!/bin/bash
COUNTER=0
while [ $COUNTER -lt 3 ]; do
let COUNTER=COUNTER+1
PROCESS=PROCESS$COUNTER
PROCESS0=00000
PROCESS1=11111
PROCESS2=22222
echo $PROCESS
done

So no matter what order I state my variables; I never get $PROCESS to equal 00000, 11111, 22222
Ultimately; once I get that far, I will create the body of my script and reference a single variable or command that will parse a different 'PROCESS' value each iteration through the loop; thus saving me from having to have a script so large it becomes unmangeable.Start Free Trial
[+][-]08.28.2007 at 08:41AM PDT, ID: 19784105

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Zones: Bourne-Again Shell (bash), Linux Programming, Scripting Languages
Tags: bash scripting
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Solution Provided By: ozo
Participating Experts: 1
Solution Grade: A
 
 
[+][-]08.28.2007 at 08:43AM PDT, ID: 19784133

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[+][-]08.28.2007 at 08:46AM PDT, ID: 19784169

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