escape commands in bash script parameter

Hi there!
is it possible to remove all sort of code injection in a parameter?

I have this ultra simple code, that uses the bash parameter in another command.
I don't want that the user has the possibility to write for example
./mybashscript '-al;rm -r /dir/;'Start Free Trial

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#
#!/bin/bash
#
if [ -z "$1" ]; then
echo 'ERROR'
exit 1
else
 
/bin/ls $1 #do command
error=$? # Preserve the exit code
 
if [ $error != 0 ]; then
echo 'ERROR'
else
echo 'OK'
fi
fi