Hi,
I have a cronjob (20 * * * * /usr/lbin/sa/sa1 300 12) that captures sar files and put them into
/var/adm/sa
server@/var/adm/sa>ll
total 1066848
-rw-r--r-- 1 root sys 17555328 Apr 2 00:15 sa01
-rw-r--r-- 1 root sys 17555328 Apr 3 00:15 sa02
-rw-r--r-- 1 root sys 17555328 Apr 4 00:15 sa03
-rw-r--r-- 1 root sys 17555328 Apr 5 00:15 sa04
-rw-r--r-- 1 root sys 17555328 Apr 6 00:15 sa05
-rw-r--r-- 1 root sys 17555328 Apr 7 00:15 sa06
-rw-r--r-- 1 root sys 16275252 Apr 7 22:30 sa07
-rw-r--r-- 1 root sys 17555328 Mar 9 00:15 sa08
-rw-r--r-- 1 root sys 16823856 Mar 10 00:15 sa09
-rw-r--r-- 1 root sys 17555328 Mar 11 00:15 sa10
-rw-r--r-- 1 root sys 17555328 Mar 12 00:15 sa11
-rw-r--r-- 1 root sys 17555328 Mar 13 00:15 sa12
-rw-r--r-- 1 root sys 17555328 Mar 14 00:15 sa13
-rw-r--r-- 1 root sys 17555328 Mar 15 00:15 sa14
-rw-r--r-- 1 root sys 17555328 Mar 16 00:15 sa15
-rw-r--r-- 1 root sys 17555328 Mar 17 00:15 sa16
-rw-r--r-- 1 root sys 17555328 Mar 18 00:15 sa17
-rw-r--r-- 1 root sys 17555328 Mar 19 00:15 sa18
-rw-r--r-- 1 root sys 17555328 Mar 20 00:15 sa19
-rw-r--r-- 1 root sys 17555328 Mar 21 00:15 sa20
-rw-r--r-- 1 root sys 17555328 Mar 22 00:15 sa21
-rw-r--r-- 1 root sys 17555328 Mar 23 00:15 sa22
-rw-r--r-- 1 root sys 17555328 Mar 24 00:15 sa23
-rw-r--r-- 1 root sys 17555328 Mar 25 00:15 sa24
-rw-r--r-- 1 root sys 17555328 Mar 26 00:15 sa25
-rw-r--r-- 1 root sys 17555328 Mar 27 00:15 sa26
-rw-r--r-- 1 root sys 17555328 Mar 28 00:15 sa27
-rw-r--r-- 1 root sys 17555328 Mar 29 00:15 sa28
-rw-r--r-- 1 root sys 17555328 Mar 30 00:15 sa29
-rw-r--r-- 1 root sys 17555328 Mar 31 00:15 sa30
-rw-r--r-- 1 root sys 17555328 Apr 1 00:15 sa31
This filled up var fast. Could you possibly help me create a script to reatin only 2 weeks of sa. I need a script to run in cron so it will check that only 2 weeks of latest data is stored in /var/adm/sa. Older than 2 weeks will be remove from the directory.
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