Question

Shell script to create csv output from log file

Asked by: keserm

I have a log files containing several thousand lines.
At the bottom of every log file there are four or five lines formated as following:

Amountname1:    1299
Amountname2:    434
Amountname3:    0
Amountname4:    14
Amountname5:    1007

I need to be able to run a cron job and read last lines with amounts to get output to csv file, something like this:

1299,434,0,14,1007

Thank you for your help.

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Asked On
2009-06-16 at 05:59:50ID24495302
Tags

shell script

Topics

Bourne Shell (sh)

,

Bourne-Again Shell (bash)

Participating Experts
3
Points
500
Comments
12

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Answers

 

by: blaazePosted on 2009-06-16 at 06:05:42ID: 24637501

can u send me sample files so that i can get the script

 

by: kesermPosted on 2009-06-16 at 06:18:16ID: 24637601

blaaze

Thank you for your replay. Unfortunately I will not be able to provide the files (proprietary).

 

by: blaazePosted on 2009-06-16 at 06:20:12ID: 24637618

or else u can use this prototype

echo " file name is"
echo $1
fd=creat($1,1)
lseek(fd,-100,SEEK_END)>blaazetemp.dat
cut -d: -f2 blaazetemp.dat
cat blaazetemp.dat

                                              
1:
2:
3:
4:
5:
6:

Select allOpen in new window

 

by: omarfaridPosted on 2009-06-16 at 06:40:54ID: 24637837

try this script

set `tail -5 filename | awk -F: '{ print $2 }'`
echo $1 , $2 , $3 , $4 , $5

 

by: oklitPosted on 2009-06-16 at 06:50:30ID: 24637959

I assume, that your log files have .log extension, and you are running this script in directory in which there are these log files.
Script takes last 4 lines and writes them to file.csv.
If your files can have sometimes 5 lines, you have to be more specific about these 4/5 lines. What is the difference between last four lines, and fifth from the end (or last five and sixth from the end)? Should script determine automatically if it should take 4 or 5 lines, or this should be specified once by you?

#!/bin/sh
 
OUTPUT=file.csv
 
for file in *.log; do
   echo `tail -n 4 ${file} | sed 's/.*:[^0-9]*//'` | tr " " "," >> ${OUTPUT}
done
                                              
1:
2:
3:
4:
5:
6:
7:

Select allOpen in new window

 

by: kesermPosted on 2009-06-16 at 07:03:14ID: 24638099

Last four or five lines are formated the same. The number of the lines depends on what log file I am looking at. This number does not have to be determine automatically.

 

by: kesermPosted on 2009-06-16 at 09:04:26ID: 24639400

Strange; here is the result I am getting from both, omarfarid and oklit solution.

,7652

It looks like it is reading last digits. Does this have anything with spaces between amount number and amount name or log file format itself - number of spaces can be different?

Amount1:  2000
Amount2:     672
Amount35:   0
Amount4:    1252
Amount55:  76

If I manually create sample log file for testing than everything works fine.

 

by: omarfaridPosted on 2009-06-16 at 09:11:38ID: 24639469

It could be, can you provide sample file (say last 5 lines of it)?

 

by: oklitPosted on 2009-06-16 at 09:22:14ID: 24639573

As omarfarid wrote - please provide last 4/5 lines from at least one file.
If there are sensitive data, change them, but leave formatting untouched! For example - replace all letters with x, and all numbers with 0. I hope that rest of characters (spaces, colons, etc) are not sensitive :)

 

by: kesermPosted on 2009-06-16 at 10:07:37ID: 24640019

Ok, here is the format of the log  files. So I need to read last five lines only and take the numbers.

AAA              A,253698517,621459,,445563223
BBB              B,253698517,621459,,445563223
CCC              A,253698517,621459,,445563223
DDD              D,253698517,621459,,445563223
EEE              E,253698517,621459,,445563223
xxxxxxxxx: 2000
xxxxx:     672
xxxxxxx:   0
xxxxxxx:   1252
xxxxxxxx:  76

Thank you!

 

by: omarfaridPosted on 2009-06-16 at 10:23:40ID: 24640195

here the results of my script:

$ cat rr
AAA              A,253698517,621459,,445563223
BBB              B,253698517,621459,,445563223
CCC              A,253698517,621459,,445563223
DDD              D,253698517,621459,,445563223
EEE              E,253698517,621459,,445563223
xxxxxxxxx: 2000
xxxxx:     672
xxxxxxx:   0
xxxxxxx:   1252
xxxxxxxx:  76
$ cat tt
set `tail -5 rr | awk -F: '{ print $2 }'`
echo $1 , $2 , $3 , $4 , $5
$ sh tt
2000 , 672 , 0 , 1252 , 76

 

by: kesermPosted on 2009-06-16 at 11:48:42ID: 31592924

Thank you for your work!

Both solutions are working.

20120131-EE-VQP-002

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