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05.15.2008 at 06:44PM PDT, ID: 23407232
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Search ID's from html file and compare it against values in an array

Tags: Shell script, perl script
I have a html file which has multiple links. All these links contains a parameter called "member=12345". Like this, I have multiple html files with different member IDs. I have a list of about 5 IDs.

What I want is to put all the IDs in an array and then run a command (which I am looking for). This command will search for the ID in "member=12345" and then see if that ID exists in the array or not. If it does, test passes, if doesn't test fails.

Please let me know ASAP as this is a critical issue and I am a starter at shell scripting.
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Question Stats
Zone: Programming
Question Asked By: desiaashik
Solution Provided By: ozo
Participating Experts: 2
Solution Grade: A
Views: 0
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05.15.2008 at 07:17PM PDT, ID: 21579437

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05.15.2008 at 07:37PM PDT, ID: 21579613

Rank: Master

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05.16.2008 at 05:27AM PDT, ID: 21582050

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05.16.2008 at 05:28AM PDT, ID: 21582058

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05.16.2008 at 08:25AM PDT, ID: 21583576

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05.16.2008 at 08:52AM PDT, ID: 21583856

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05.16.2008 at 11:01AM PDT, ID: 21585010

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05.18.2008 at 06:59PM PDT, ID: 21594853

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05.15.2008 at 07:17PM PDT, ID: 21579437
provide a sample file
 
05.15.2008 at 07:37PM PDT, ID: 21579613

Rank: Master

cat >  list <<END
"member=12345"
"member=12346"
"member=12347"
"member=12348"
END

grep -f list file.html
 
05.16.2008 at 05:27AM PDT, ID: 21582050
Attached is the sample file. Basically, I need to find and compare each instance of ref=123456789 to the ref that is in an array.

The sample array will look something like this: (123456789, 4589754689, 78445697, 568515699)

I want to find values of each "ref" from URL and make sure that it belongs to the array. If it does, test passed. If doesn't, test failed and an email is sent.
 
05.16.2008 at 05:28AM PDT, ID: 21582058
sorry, forgot to attach the file.
 
it is actually an html file but this won't allow me to upload html so turned it into a txt file
 
 
05.16.2008 at 08:25AM PDT, ID: 21583576
1:
2:
3:
4:
5:
awk '/ref/ && /zip/ {
 val=gensub(/.*ref=(.*)&zip.*/,"\\1","g",$0)
 print val
}
' file
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Assisted Solution
 
05.16.2008 at 08:52AM PDT, ID: 21583856
I tried this and I get error. maybe I am using it a wrong way. I get error "input record number 1" (don't know what that means)

I am a newbie to this and the command itself is complex. Any other simple ideas?
 
05.16.2008 at 11:01AM PDT, ID: 21585010

Rank: Master

perl -lne 'BEGIN{$_=join"|",splice @ARGV; s/[|\s,]+/|/g;s/[()]//g;$re=qr/\bref=(?!(?:$_)\b)\d+/}print for /$re/g' '(4589754689, 78445697, 568515699)' < acooking051608.txt
Accepted Solution
 
05.18.2008 at 06:59PM PDT, ID: 21594853
@ozo, i think you should use code tags and indent the perl code for the beginner to understand.
@OP, if your machine do not have GNU awk, then you may not be able to use gensub. Try ozo's solution, if you can understand it.
 
 
20080236-EE-VQP-29 / EE_QW_2_20070628