Question

Validate string

Asked by: Edward98

Hi, I need some help with string validation.
I need to perform a test on a couple of strings one to see if holds "-1234" the last 5 carecters of a phone# and another string to see if it holds  ".com".
Any help would be most appreciated!
TIA

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Asked On
1999-10-04 at 01:47:23ID10214517
Topic

Visual Basic Programming

Participating Experts
4
Points
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Comments
5

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Answers

 

by: Edward98Posted on 1999-10-04 at 01:57:11ID: 2096030

Edited text of question.

 

by: setiawanPosted on 1999-10-04 at 02:16:48ID: 2096067

It is very easy, you can use right function

If Right(yourstring,5) = "-1234" Then
    .....
End If

If UCase(Right(yourstring, 4)) = ".COM" Then
   ....
End If
 
  danny

 

by: ferkelPosted on 1999-10-04 at 02:24:26ID: 2096088

Let c$ be the string to be tested:
1. to test for ".com" at the end
    ' Test is done case sensitive, i.e. ".COM" will not match ".com"
    if right$(c$,4) = ".com" then
       ' success
    else
      ' fail
    endif

    ' change the condition not to be case sensitive to
    if UCase$(Right$(c$,4)) = ".COM" then

2. to test for c$ contain -1234 (minus followed by 4 digits) at the end
    Dim tail as String
    dim ok as boolean
    Dim i as integer
    ' Assume the check failed
    ok = False
    ' get the 5 last chars
    tail = Right$(C$,5)
    ' first check: the tail must be at least 5 chars long
    if len(tail) = 5   then
      ' if so, the first char must be a minus
      if left$(tail,1) = "-" then
         ' check last four for being digits
         ok = true
         for i = 2 to 5
             ok = ok and is_digit(mid$(tail,i,1)
         next i
      endif
    endif
   
    ' if ok=TRUE at this point, c$ contains a minus followed by 4 digits at the end:
    if ok then
      ' success
    else
      ' failure
    endif  
 
the function is_digit must be defined as follows:

private function is_digit ( c as string ) as boolean
   is_digit = left$(c,1) >= "0" and left$(c,1) <= "9"
end function
 

 

by: turePosted on 1999-10-04 at 05:29:13ID: 2096441

Edward98,

The easiest way is to use the LIKE operator:

If x Like "*-1234" Then
  MsgBox "Text ends with -1234"
End If

If Lcase(x) Like "*.com*" Then
  MsgBox "Text contains .com"
End If

Ture Magnusson
Karlstad, Sweden

 

by: MoondancerPosted on 2002-03-12 at 18:01:52ID: 6859081

This question was awarded, but never cleared due to the JSP-500 errors of that time.  It was "stuck" against userID -1 versus the intended expert whom you awarded.  This corrects the problem and the expert will now receive these points; points verified.

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Thank you,
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