Question

mod 11 vb code for check digit again URGENT

Asked by: awolfe76

ok i posted this question before but without any really good information on it. i now have good information. so here is it.
i need check digit code, using mod 11, for an 11 digit number, the final(11th) digit is the check digit. the user will enter the 11 digit number into a text box, when they click the submit button the code should run on the number to validate it. it will tell whether or not check digit number is what it should be.

NCS MOD 11 CHECK DIGIT ROUTINE FOR 10 DIGIT NUMBER:              
                                                                 

A SERIES OF MULTIPLICATIONS AND ADDITIONS IS PERFORMED, WITH THE      

MULTIPLICATION RESULTS BEING ADDED TO A FINAL COUNTER.  ON            

COMPLETION OF ALL MULTIPLICATIONS, THE COUNTER ID DIVIDED BY 11,      

AND 11 IS SUBTRACTED FROM THE REMAINDER.  THE LAST DIGIT OF THIS      

SUBTRACTION IS THE CHECK DIGIT.                                      

                                                                 

EXAMPLE:  FINDER NUMBER - TOTAL OF 11 POSITIONS     RESULT            
                                                                     

          1438623406 C(CHECK DIGIT)                      0 (INITIAL VALUE)    

                                                                     

THE 10TH DIGIT IS MULTIPLIED BY 3    (6 X 3 = 18)   +   18            

                                                    ------            

                                                        18            

THE 9TH DIGIT IS MULTIPLIED BY 5     (0 X 5 = 0)    +    0            

                                                    ------            

                                                        18            

THE 8TH DIGIT IS MULTIPLIED BY 7     (4 X 7 = 28)   +   28            

                                                    ------      

                                                        46      

THE 7TH DIGIT IS MULTIPLIED BY 9     (3 X 9 = 27)   +   27      

                                                    ------      

                                                        73      

THE 6TH DIGIT IS MULTIPLIED BY 11    (2 X 11 = 22)  +   22      

                                                    ------      

                                                        95      

THE 5TH DIGIT IS MULTIPLIED BY 13    (6 X 13 = 78)  +   78      

                                                    ------      

                                                       173      

THE 4TH DIGIT IS MULTIPLIED BY 15    (8 X 15 = 120) +  120      

                                                    ------      

                                                       293      

THE 3RD DIGIT IS MULTIPLIED BY 17    (3 X 17 = 51)  +   51      

                                                    ------      

                                                       344      

THE 2ND DIGIT IS MULTIPLIED BY 19    (4 X 19 = 76)  +   76      

                                                    ------      

                                                       420      

THE 1ST DIGIT IS MULTIPLIED BY 21    (1 X 21 = 21)  +   21      

                                                    ------  

                                                       441  

                                                             

THIS RESULT IS DIVIDED BY 11:  441/11 = 40, WITH REMAINDER 1
                                                           

11 IS SUBTRACTED FROM THE REMAINDER: 1 - 11 = -10            
                                                             

THE LAST DIGIT OF THIS SUBTRACTION (0) IS THE CHECK DIGIT

i hope that this helps. again its urgent. and i appreciate all the help. thanks in advance.

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Asked On
2003-10-03 at 07:54:41ID20756282
Tags

check

,

code

,

digit

Topic

Visual Basic Programming

Participating Experts
1
Points
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Comments
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Answers

 

by: wuttrainPosted on 2003-10-03 at 08:56:58ID: 9485668

this should help you get started. hope this helps

'iStartMultiply = 3, first value of the mulltiplier
'iStep = 2, the increment value

Function CheckDigit(strString As String, iStartMultiply As Integer, iStep As Integer) As Integer
Dim i As Integer
Dim iNum As Integer
Dim iProd As Long
Dim iSum As Long
Dim iRemainder As Integer
Dim iQuo As Long
Dim iResult As Integer

  iSum = 0
  For i = 10 To 1 Step -1
    iNum = Mid(strString, i, 1)
    iProd = iNum * iStartMultiply
    iStartMultiply = iStartMultiply + iStep
    iSum = iSum + iProd
  Next i

  iRemainder = iSum Mod 11
  iQuo = iSum / 11
  iResult = iRemainder - 11
  CheckDigit = Right(Trim(Str(iResult)), 1)
End Function

Private Sub Command1_Click()
    txtOutput.Text = CheckDigit(txtInput.Text, 3, 2)
End Sub

 

by: awolfe76Posted on 2003-10-05 at 06:50:33ID: 9494350

that does it exactly sorry it took so long to get back to you on this busy with somethign else but thanks alot.

20120131-EE-VQP-002

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