Ret = Abs(4 - Len(CStr(YourNum)))
FormatNum = String(Ret, "0") & YourNum
FormatNum is the number correctly formatted for this, and YourNum should be replaced with the variable holding the number you want to format
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Question
Keeping a number as a lenth=4 string
I have a string called CustomerID and I need it in the format 0003, 0014 etc... this is what I have, but my problem is if I enter a number say 13 it gives me 00013 when I really want 0013. It is the select case part of the function that the problem lays I think.
'Creates a new JobID
Public Function NewJobID() As String
Dim JobID As String, Counter As Single
JobID = LastJobID + 1
LastJobID = LastJobID + 1
Call UpdateLastIDs
Select Case JobID
Case 1 To 9
NewJobID = "000" & JobID
Case 10 To 99
NewJobID = "00" & JobID
Case 100 To 999
NewJobID = "0" & JobID
Case 1000 To 9999
NewJobID = JobID
End Select
End Function
Thanks, Jebus
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by: dj__jebusPosted on 2003-11-07 at 22:59:18ID: 9706198
lol, woops I said CustomerID oh well, I have identical functions for both CustomerID and JobID, same thing...