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August 29, 2008 03:00pm pdt
 
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Trouble getting connected to an Access db that has an ODBC linked table

Tags: VB
I have simplified the problem to this:  I have an Access database (C:\test.mdb) that has two tables.  One is linked to a table in Northwind.mdb.  The other is linked to a table in a database through an ODBC connection.  

The link to Northwind works fine.  I have some syntax issue with the ODBC connection.

When I linked the table in Access I first had to set up a "Machine Data Source".  Then I had to provide a Data Source Name and a "Login ID".  There is no password to the database.  I'm sure this is the part that I am messing up.

I have attached my code and the database.  Of course the links to the tables will not work.
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Private Sub Form_Load()
    Dim dbLinked As ADODB.Connection
    Dim rsLinked As ADODB.Recordset
    Dim sLinked As String
 
    Dim dbODBCLinked As ADODB.Connection
    Dim rsODBCLinked As ADODB.Recordset
    Dim sODBCLinked As String
 
'Get LinkID.
    Set dbLinked = New ADODB.Connection
    Set rsLinked = New ADODB.Recordset
    dbLinked.Open "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=c:\test.mdb"
    sLinked = "SELECT LinkedData.ProductName From LinkedData ORDER BY LinkedData.ProductName;"
    rsLinked.Open (sLinked), dbLinked
    
    Debug.Print "Linked:  "; rsLinked!ProductName
    
'Get ODBCImportedID.
    Set dbODBCLinked = New ADODB.Connection
    Set rsODBCLinked = New ADODB.Recordset
    dbODBCLinked.Open "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=c:\test.mdb"
    sODBCLinked = "SELECT ODBClinkedData.ProductName From ODBClinkedData ORDER BY ODBClinkedData.ProductName;"
'The next line is the one giving me trouble.  The error is "No value given for one or more required parameters."
    rsODBCLinked.Open (sODBCLinked), dbODBCLinked, , , False
    
    Debug.Print "ODBCImported:  "; rsODBCLinked!ProductName
    
End Sub
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Question Stats
Zone: Programming
Question Asked By: randys106
Solution Provided By: TimCottee
Participating Experts: 1
Solution Grade: B
Views: 0
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Accepted Solution by TimCottee:

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[+][-]Author Comment by randys106
Author Comment by randys106:

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