Question

Split String into smaller chunks

Asked by: Pigdogmonster

hi - thanks for looking at my question.

I am printing to labels using VBscript and would like to change a string to handle this.
I have a string that will be no more than 50 chars.

I would like to split the string into 4 smaller strings.

i.e.
varMainString="17*140 TORUS SKIRT 2.4M 4PCS (12) PEFC MIN 70% EAN"

varString1="17*140 TORUS"
varString2="SKIRT 2.4M 4PCS"
varString3="(12) PEFC MIN "
varString4="70% EAN"

No string can be more than 15 chars (inc spaces) or the line will not be printed and I would like to always have 4 strings even if they are blank.


Please see the attached scan and this will give you an idea of what I would like.

Thanks in advance

Stuart

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Asked On
2009-10-28 at 09:44:00ID24851649
Topics

VB Script

,

Active Server Pages (ASP)

Participating Experts
1
Points
125
Comments
5

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Answers

 

by: QlemoPosted on 2009-10-28 at 10:26:52ID: 25685858

I recommend to use the Split function to create an array of strings, split on space:
 splits = Split(varMainString)

In a loop, add the next string fragment to the previous, and look if it 15 max. If not, do not add, and use next var (best again as an array):

Dim target(4)
j = 0
for each x in splits
 if len(target(j)+x) > 14 then
    j = j+1
else
   target(j) = target(j) + " " + x
end if
next i

Then you only need to use target(0) etc.

 

by: PigdogmonsterPosted on 2009-10-29 at 02:24:37ID: 25691777

Hi Qlemo,

Thanks.

How do I put this is my code?

I have this:-

I would like it to appear like this:-

target = "17*140 TORUS SKIRT 2.4M 4PCS (12) PEFC MIN 70% EAN"

ReplaceToken msLabelTemplate, "@LABEL6@", "17*140 TORUS"
ReplaceToken msLabelTemplate, "@LABEL7@", "SKIRT 2.4M 4PCS"
ReplaceToken msLabelTemplate, "@LABEL8@", "(12) PEFC MIN"
ReplaceToken msLabelTemplate, "@LABEL9@", "70% EAN"

The LABEL names are hardcoded 6-9.  I just need to incorporate your code into this.

Any ideas?

many thanks

Stuart


 

by: QlemoPosted on 2009-10-29 at 13:10:43ID: 25697739


target = "17*140 TORUS SKIRT 2.4M 4PCS (12) PEFC MIN 70% EAN"
 
Dim splits(4)
j = 0
for each x in Split(target)
 if len(splits(j)+x) > 14 then
    j = j+1
else
   splits(j) = splits(j) + " " + x
end if
next i
 
ReplaceToken msLabelTemplate, "@LABEL6@", splits(0)
ReplaceToken msLabelTemplate, "@LABEL7@", splits(1)
ReplaceToken msLabelTemplate, "@LABEL8@", splits(2)
ReplaceToken msLabelTemplate, "@LABEL9@", splits(3)
                                              
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by: PigdogmonsterPosted on 2009-10-30 at 02:31:31ID: 25701292

Hi,

This seems to work but it misses out some of the text for some reason.

Here is my code:-

target = "17*140 TORUS SKIRT 2.4M 4PCS (12) PEFC MIN 70% EAN"
 
Dim splits(4)
j = 0
for each x in Split(target)
 if len(splits(j)+x) > 14 then
    j = j+1
else
   splits(j) = splits(j) + " " + x
end if
next i
 
ReplaceToken msLabelTemplate, "@LABEL6@", splits(0)
ReplaceToken msLabelTemplate, "@LABEL7@", splits(1)
ReplaceToken msLabelTemplate, "@LABEL8@", splits(2)
ReplaceToken msLabelTemplate, "@LABEL9@", splits(3)

Please see the attached scan of the label when it prints, as you can see it misses 'SKIRT' and 'PEFC'.

any ideas why?

Regards

Stuart

  • label.jpg
    • 270 KB

    Label is missing information from varDescription

    Label is missing information from varDescription
 

by: QlemoPosted on 2009-10-30 at 04:46:03ID: 25701936

Urghh. My fault. After "line break" (next line), the code is skipping the text fragment ...

target = "17*140 TORUS SKIRT 2.4M 4PCS (12) PEFC MIN 70% EAN"
 
Dim splits(4)
j = 0
for each x in Split(target)
 if len(splits(j)+x) > 14 then j = j+1
 splits(j) = splits(j) + " " + x
next i
 
ReplaceToken msLabelTemplate, "@LABEL6@", splits(0)
ReplaceToken msLabelTemplate, "@LABEL7@", splits(1)
ReplaceToken msLabelTemplate, "@LABEL8@", splits(2)
ReplaceToken msLabelTemplate, "@LABEL9@", splits(3)

                                              
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20120131-EE-VQP-002

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