Question

C#: RegEx to find string w. 2 vars

Asked by: Smoerble

Hoi all.
I need your help for the followingissue in C#:
I need to find a substring in a string. This substring contains 2 parameters. Exmaples:
-------------
Example1:
stringWhetever = "some text <callMethod=24,7>some more text"
-------------
Example2:
stringWhetever = "<callMethod=89,17> some text <callMethod=24,7> some more text"
-------------
Example3:
stringWhetever = "some text  some more text"
-------------

I need a solution in C# to replace this substring with a function that uses these 2 parameters.
Moethod code:
-------------
public string callMethod(int varOne, int varTwo) {
    return "return string "+varOne+" and "+varTwo;
}
-------------

So I need a Regular Expression, that finds the substring.
Then I need to replace all (if any) of the found sub strings and replace like this (pseudo code!!!!):

stringWhetever.Replace(regExMatch, callMethod(regExMatchValue1, regExMatchValue1)).

Hope, someone can help me.

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Asked On
2004-05-21 at 07:06:36ID20997656
Tags

regex

,

find

,

string

Topics

Miscellaneous Programming

,

Regular Expressions

Participating Experts
3
Points
500
Comments
4

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Answers

 

by: prasitleePosted on 2004-05-21 at 08:49:41ID: 11127837

Hi Smoerble,
    Can you give me the exact details of what you want again ? I am not sure if I understand correctly or not.
                                                                  Meng

 

by: jkozeePosted on 2004-05-21 at 13:53:36ID: 11130188

I don't have access to c#, but here it is in VB6.  Should be easy enough to convert?

Dim oRE As New RegExp
Dim oMatch As Match
Dim oMatches As MatchCollection
Dim oSubMatches As SubMatches

Dim s As String
 
s = "some text <callMethod=24,7> some more text <callMethod=13,6> and some more text"

With oRE
    'Need to search for all occurences
    .Global = True
    .MultiLine = True
    .Pattern = "<callMethod=(\d*),(\d*)>"
   
    Set oMatches = .Execute(s)
   
    'Don't want to replace all occurences at once
    .Global = False
End With

For Each oMatch In oMatches
    Set oSubMatches = oMatch.SubMatches
    s = oRE.Replace(s, CallMethod(oSubMatches(0), oSubMatches(1)))
Next oMatch

Debug.Print s

Public Function CallMethod(i1 As Integer, i2 As Integer) As String
    CallMethod = "Return string " & i1 & " and " & i2
End Function

Gives the following result.
"some text Return string 24 and 7 some more text Return string 13 and 6 and some more text"

Sorry if this MUST be in c#.  Let me know and I'll see if I can't help convert it.

John

 

by: jkozeePosted on 2004-05-21 at 13:58:37ID: 11130240

Oops.  Better to change:

    .Pattern = "<callMethod=(\d*),(\d*)>"
to:
    .Pattern = "<callMethod=(\d+),(\d+)>"

To force a match of at least one digit.

 

by: fluffyerugPosted on 2004-06-10 at 16:16:18ID: 11284493

Here is the C# version

            private string Method(int intVarOne, int intVarTwo, string strTemp)
            {
                  System.Text.RegularExpressions.Regex  oRe;
                  System.Text.RegularExpressions.MatchCollection oMatches;

                  
                  oRe = new System.Text.RegularExpressions.Regex ("<callMethod=(\\d+),(\\d+)>");
                  oMatches =  oRe.Matches(strTemp);
                  
                  foreach (System.Text.RegularExpressions.Match oMathch in oMatches)
                  {
                        strTemp  = strTemp.Replace (oMathch.ToString() ,CallMethod(intVarOne ,intVarTwo ));
                  }

                  return strTemp;
            }
            private string CallMethod(int intOne, int intTwo)
            {
                  return "Return string " + Convert.ToString(intOne) + " and " + Convert.ToString (intTwo);
            }

Best Regards

Fluff

20120131-EE-VQP-002

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