Question

VB - How do I find the second instance of a character within a string?

Asked by: FJRMill

Hi experts

Is it possible to use the INSTR function to return the location of the second instance of a character within a string?

Thanks for you help :)

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Asked On
2008-01-05 at 08:53:05ID23060880
Tags

instance

,

character

,

second

,

find

,

string

Topics

Miscellaneous Programming

,

Visual Basic Programming

,

Visual Studio

Participating Experts
1
Points
500
Comments
4

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Answers

 

by: PaulHewsPosted on 2008-01-05 at 08:59:15ID: 20589624

Option Explicit

Private Sub Command1_Click()
    Dim strTest As String
    strTest = "this is a test"
    Debug.Print GetSecondPos(strTest, "t")
   
End Sub

Private Function GetSecondPos(strText As String, strSub As String) As Long
    Dim lngPos As Long
    lngPos = InStr(1, strText, strSub)
    If lngPos > 0 Then
        lngPos = InStr(lngPos + 1, strText, strSub)
    End If
    GetSecondPos = lngPos
End Function

 

by: FJRMillPosted on 2008-01-05 at 09:15:07ID: 20589693

Hi Paul - thanks for your quick response.

I have tried your function but get an error:

Error      1      Overload resolution failed because no accessible 'InStr' can be called without a narrowing conversion:
    'Public Function InStr(Start As Integer, String1 As String, String2 As String, [Compare As Microsoft.VisualBasic.CompareMethod = Microsoft.VisualBasic.CompareMethod.Binary]) As Integer': Argument matching parameter 'Start' narrows from 'Long' to 'Integer'.
    'Public Function InStr(String1 As String, String2 As String, [Compare As Microsoft.VisualBasic.CompareMethod = Microsoft.VisualBasic.CompareMethod.Binary]) As Integer': Argument matching parameter 'String1' narrows from 'Long' to 'String'.
    'Public Function InStr(String1 As String, String2 As String, [Compare As Microsoft.VisualBasic.CompareMethod = Microsoft.VisualBasic.CompareMethod.Binary]) As Integer': Argument matching parameter 'Compare' narrows from 'String' to 'Microsoft.VisualBasic.CompareMethod'.


I'm building a VB windows forms app in Visual Studio 2005



 

by: FJRMillPosted on 2008-01-05 at 09:17:40ID: 20589713

.. Got it!

I just changed "Dim lngPos As Long"  to "Dim lngPos As integer".

Thanks for your help!

Mill

 

by: PaulHewsPosted on 2008-01-05 at 09:53:28ID: 20589871

That's VB6 code I posted above.  In VB.NET this would be better:

Public Class Form1
 
    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim Test As String = "this is a test"
        Debug.WriteLine(GetSecondPos(Test, "t"c).ToString)
 
    End Sub
 
    Private Function GetSecondPos(ByVal TextString As String, ByVal SearchChar As Char) As Integer
        Dim Pos As Integer = TextString.IndexOf(SearchChar)
        If Pos > -1 Then
            Pos = TextString.IndexOf(SearchChar, Pos + 1)
        End If
        Return Pos
    End Function
 
 
End Class
                                              
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