DIFFERENCE OF TWO DATES

Any body ho will give the Ans I will be pleased to see the Answer of that Question

https://www.experts-exchange.com/questions/20394123/Difference-of-two-dates.html
So it's now a 60 point question :)

#include<stdio.h>
struct date {
        int MM,DD,YYYY;
};

int days[13]={0,31 ,28,31,30,31,30,31,31,30,31,30,31};
int leap=0;
struct date sub(struct date d1,struct date d2) {
        struct date temp;
        temp.DD = d1.DD - d2.DD;
        temp.MM = d1.MM - d2.MM;
        temp.YYYY = d1.YYYY-d2.YYYY;
        if(temp.MM<0){
                temp.MM += 12;
                temp.YYYY -=1;
        }
        if(temp.DD<0){
                if(temp.MM<1) {
                        temp.MM +=12;
                        temp.YYYY -=1;
                }
                temp.MM -=1;
                temp.DD += days[d1.MM]+leap; /*temp.MM];*/
                /* 31 ,28,29,30 will depend on
                 * temp.MM , i.e. iif it is
                 * 1 then 31 , 2 the 28/29 etc.*/
        }
        return temp;
}

main(){
        struct date d1,d2,d3;
        printf("\nEnter date one MM DD YYYY format : ");
        scanf("%d%d%d",&d1.MM,&d1.DD,&d1.YYYY);
        leap = (d1.YYYY %4 ==0)?1:0;
        printf("\nEnter date two MM DD YYYY format : ");
        scanf("%d%d%d",&d2.MM,&d2.DD,&d2.YYYY);
        d3=sub(d1,d2);
        printf("\nsub: \ndays: %d months: %d years: %d ",d3.DD,d3.MM,d3.YYYY);
        exit(0);
}

/* please make some changes for leap yr if necessary */

Sorry, in above soln
comment at line # 23 is :
/* 31 28 30 .. etc will depend on d1.MM and leap
not on temp.MM */
/* thanks */

Nothing has happened on this question in more than 13 months. It's time for cleanup!

My recommendation, which I will post in the Cleanup topic area, is to
accept answer by ozo (it's a duplicate question, but ozo's solution is too elegant to delete).

PLEASE DO NOT ACCEPT THIS COMMENT AS AN ANSWER!

jmcg
EE Cleanup Volunteer