Converting a string to char array

Hello I have the following code:

#include <iostream.h>
#include <fstream.h>
#include <string>
#include <iomanip>

int length(const char* str)
{
      int length;
      for (int i=0;str[i]!='\0'; i++)
      {
            length=i;
      }

      return length;
}

void break_lines(string buf)
{
      const char* str;
      strcpy(str, buf); <<<-------------------------- HERE

      int l = length(str);
      char buffer[l+1];
      for (int i=0, j=0;i<=l; i++)
      {
            if (str[i] != ' ')
            {
                  buffer[j] = str[i];
            }
            else
            {
                  cout << buffer << endl;
            }
      }
      
}

int readFile()
{
      ifstream inFile("rules.txt");

      string line;

      while (!inFile.eof())
      {
          getline(inFile, line);
            break_lines(line);
          cout<<line<<endl;
      }

      inFile.close();
      return 0;
}

int main()
{
      readFile();

      return 0;
}


I would like to convert the "buf" variable to "str" character array but I get the following error:

c:\applications\quincy99\assignment\start.cpp: In function `void break_lines(basic_string<char,string_char_traits<char>,__default_alloc_template<false,0> >)':
c:\applications\quincy99\assignment\start.cpp:20: passing `const char *' as argument 1 of `strcpy(char *, const char *)' discards qualifiers
c:\applications\quincy99\assignment\start.cpp:20: cannot convert `buf' from type `string' to type `const char *'

Any help of how I can do it is appreciated.

I am using the g++ compiler.

Regards

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