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VB Simple Question (easy 50 pts)

Here it is:

I want the user to type in as string like (I go to VB school) into a textbox. Each time the user clicks a command button, it will capture the location of the space and the string before space. e.g. when the user click a command button for first time, it shows location of space AND character which is "I", when the user click a command button for second time, it shows the location of the space again, and "go".....etc.

It is pretty straight forward, but I would like to know the logic more than anything else.

ASKER CERTIFIED SOLUTION

rspahitz

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Crash2100

Dim strings() As String
Dim counter As Integer
Dim iLocation As Integer

Private Sub Command1_Click()
iLocation = Len(strings(counter)) + 1

MsgBox "String: " & strings(counter) & vbCrLf & "Location: " & iLocation

If counter = UBound(strings) Then
counter = 0
Else
counter = counter + 1
End If
End Sub

Private Sub Form_Load()
strings = Split(Text1.Text, " ")
End Sub

Crash2100

sorry, try this:

Dim strings() As String
Dim counter, x As Integer
Dim iLocation As Integer

Private Sub Command1_Click()
iLocation = 0
For x = 0 To counter
iLocation = iLocation + Len(strings(x)) + 1
Next x

If iLocation < Len(Text1.Text) Then
MsgBox "String: " & strings(counter) & vbCrLf & "Location: " & iLocation
Else
MsgBox "String: " & strings(counter) & vbCrLf & "No space after"
End If

If counter = UBound(strings) Then
counter = 0
Else
counter = counter + 1
End If
End Sub

Private Sub Form_Load()
strings = Split(Text1.Text, " ")
End Sub

MysticJim

Private Sub Command1_Click()
Static lFirstSpacePos As Long
Static lSecondSpacePos As Long

lFirstSpacePos = lSecondSpacePos

If lFirstSpacePos = 0 Then
lFirstSpacePos = 1
End If

lSecondSpacePos = InStr(lFirstSpacePos + 1, Text1.Text, " ", vbTextCompare)

If lSecondSpacePos = 0 Then
lSecondSpacePos = Len(Text1.Text) + 1
Else
lSecondSpacePos = lSecondSpacePos + 1
End If

Text1.SelStart = lFirstSpacePos - 1
Text1.SelLength = lSecondSpacePos - lFirstSpacePos
Call Text1.SetFocus

End Sub

TimCottee

MysticJim, I feel sure that you have been warned previously in respect of comments vs answers. Please reread the guidelines at the bottom of the page and do not post answers in this way in future. Should you continue to do so your account WILL be referred to customer services for possible penalty.

rspahitz

ghadley, are you still with us?

My original code works with one minor issue--it highlights the character after the space. To fix it, subtract one from the SelStart value:

Text1.SelStart = intSpacePosition - 1

Also, you won't see where the selection is if the textbox does not have the focus, so also add this at the end of the Command1_Click procedure:
Text1.SetFocus

The new code for Command1_Click will be:

Private Sub Command1_Click()
Dim intSpacePosition As Integer

m_intSpaceCounter = m_intSpaceCounter + 1
intSpacePosition = FindSpaceInText(Text1.Text, m_intSpaceCounter)
If intSpacePosition = 0 Then
Text1.SelLength = 0
Else
Text1.SelStart = intSpacePosition - 1
Text1.SelLength = 1
End If
Text1.SetFocus
End Sub

....
MysticJim, since you posted your code as a solution, rather than the preferred comment, please explain why/how it is better than the code that I already offered...
(BTW, you defined the variable counter as a variant!)

ghadley

ASKER

I do not need to see highlight, i actually ask for msgbox to show the location of space and string.

Can you try again?

ghadley

ASKER

I do not need to see highlight, i actually ask for msgbox to show the location of space and string.

Can you try again?

rspahitz

change the Command1_Click procedure to:

private sub Command1_Click()
dim intSpacePosition as integer

m_intSpaceCounter=m_intSpaceCounter+1
intSpacePosition = FindSpaceInText(Text1.Text, m_intSpaceCounter)
if intSpacePosition=0 then
msgbox "no more spaces", vbokonly or vbexclamation
else
msgbox "space found at position " & (intSpacePosition - 1), vbokonly or vbinformation
endif
end sub

Crash2100

ghadley, look at the second set of code I posted

Netminder

Computer101

ghadley,
I have made it clear my intentions. Recommend you post in your open questions or your account will be suspended. The initial request was for 72 hours but seeing you have subscribed to E-E since then, consider this your time limit.

Computer101
E-E Admin

Netminder

Question abandoned; force-accepted and Admin notified.

Crash2100: points for you at https://www.experts-exchange.com/questions/20389226/For-Crash2100-re-20303268.html

Netminder
CS Moderator