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05.11.2006 at 10:38AM PDT, ID: 21847192
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7.4

Undesirable early termination - Bash shell scripting while loop

Asked by lennagy in Linux Programming

Tags: , , ,

I've created a bash shell script that loops through a command file.  This command file performs a range of tasks across a range of servers.

WORKS: If I place 'echo' in front of the commands within the loop, then it will show a simulated execution of all tasks on all servers in the list.

DOESNT WORK: After I remove the 'echo' then it will successfully perform all the tasks for the first server, then never do anything for the subsequent servers!

A heavily edited version for clarity and security of the code is as follows ... ( these are the major utilities used in actual script )

while read recLabel recSourcePath recDestinationServer recDestinationPath recDestinationFile
do
  ssh ${recDestinationServer} mkdir ${recDestinationPath}
  ssh ${recDestinationServer} rm ${recDestinationPath}/*.tar.gz
  rsync -baz -e ssh ${recSourcePath }/${recDestinationFile} username@${recDestinationServer }:${recDestinationPath }
done < ${parmFileList}

... sample parmFileList ...
app1 /opt/app1/data webserver1 /tmp/update 1.tar.gz
app1 /opt/app1/data webserver2 /tmp/update 1.tar.gz
app1 /opt/app2/data appserver1 /tmp/update 3.tar.gz
app1 /opt/app2/data appserver2 /tmp/update 3.tar.gz

Any thoughts?

I've put in place a temporary solution, which was to cut all the loop code and create another script.  I call that script from the loop context with a split of the pid using '&'
This of course works, as parallel; however, I'm still curious why it won't run through the whole parmFileList as this is posted.




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Zone: Linux Programming
Tags: loop, while, bash, shell
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Solution Provided By: Nopius
Participating Experts: 3
Solution Grade: A
 
 
[+][-]05.17.2006 at 12:27PM PDT, ID: 16702614

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