Question

Obtaining ROOT privileges in program run by user

Asked by: kyleb84

I'm writing an app that needs to read the MBR record of the disk, for this it must have root access but it must only be run by a user.

Command line solutions are not an option.

Is there a way of temporarily impersonating root via code in my program?

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Asked On
2009-11-04 at 04:23:20ID24870611
Tags

root

,

sudo

,

C

,

C++

Topics

Linux Programming

,

Open Source Programming

,

C Programming Language

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Answers

 

by: nociPosted on 2009-11-04 at 05:10:34ID: 25738895

Yes you can do it through a commandline using sudo + sudo config.   run something like
system("sudo dd if=/dev/sda of=/tmp/mymbr bs=512 count=1").

Or you can write a small program, that has setuid bit set and is owned by root, causing it to run with root uid.

Dont make the whole app privileged, otherwise you will have to audit it for buffer overflows and other misshaps to prevent accidental root access. (anything started by that program will f.e. run also as root).

 

by: omarfaridPosted on 2009-11-04 at 08:34:02ID: 25741048

 

by: kyleb84Posted on 2009-11-04 at 13:53:27ID: 25744368

I stated that command line solutions are not an option.

 

by: nociPosted on 2009-11-04 at 15:11:31ID: 25745129

please read the second line of the first comment.....

You can start an other program (with root preperties, that can only read the boot sector of a disk and write it into a pipeline you read in your own program.....)

the way it works is: (sortof, you have to readup on details for pipe(), fork(), execv*()...)

int channels[2];
pipe(channels)
if (fork()==0) {
  close (channel[1]);
  close(1);
  dup(channel[0]);
  close(channel[0]);
  execv("/opt/myapp/mbrreader","mbrreader","/dev/hda");
  exit(200);
} else {
   close(channels[0]);
   read(channels[1], mbrbuffer,sizeof(mbrbuffer))
   close (channels[1]);
}




your mbrreader.c, after compilation: chown root mbrreader, chmod o+sx mbrreader.
main()
{
    fd= open(argv[1],"r");
    read(fd,mbr,512);
    write(1,mbr,512);
    exit(0);
}


Check for errors etc..

 

by: kyleb84Posted on 2009-11-04 at 16:31:45ID: 25745704

noci,

Seems like it's exactly what I was looking for, shall slap it it compile and see how it goes...

Cheers.

 

by: nociPosted on 2009-11-04 at 18:05:35ID: 25746157

it needs some work though, you can only use the above as a guide.../pseudo code.

 

by: kyleb84Posted on 2009-11-05 at 04:34:18ID: 25748741

I've been fiddling with the below code, and still cant get it going!

Can you see anything wrong with it?

Cheers,

KB.

Makefile to suite, if you care to compile...

--------CUT-----------
all: printmbr

printmbr: printmbr.o
      gcc printmbr.o -o printmbr

printmbr.o: printmbr.c
      gcc -c printmbr.c

clean:
      rm -rf *o printmbr
--------CUT-----------

#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <unistd.h>
#include <errno.h>
#include <stdlib.h> 
#define PIPE_PARENT 0
#define PIPE_CHILD 1 
int main (int argc, char *argv[])
{ 
  int channels[2]; 
  char mbr[512]; 
  pipe(channels); 
  pid_t pid = fork(); 
  if (pid == 0) { 
    // Child process, close parent's end.
    close (channels[PIPE_PARENT]); 
    // Close STDOUT
    close(1); 
    // Duplicate the child channel to STDOUT
    dup2(channels[PIPE_CHILD], 1); 
    // Close our old channel fd
    close(channels[PIPE_CHILD]); 
    // Execute a file, hopefully anything it prints to STDOUT shoots straight through
    // our channel[PIPE_CHILD]
    execv("echo","Test message!"); 
    exit(100); 
  } else if (pid > 0) { 
    // Parent, close childs end.
    close(channels[PIPE_CHILD]); 
    // Open the parent's end
    FILE *f = fdopen(channels[PIPE_PARENT], "r"); 
    if (f == NULL) {
      printf("ERROR: Failed to open channel PIPE_PARENT, errno = %d\n", errno);
    } else {
      // Should read the char 'T'...
      printf("fread(PIPE_PARENT): %d, errno = %d\n", fread(&mbr, 1, 1, f), errno);
      fclose(f);
    } 
    close(channels[PIPE_PARENT]); 
  } else { 
    // Failure
    printf("ERROR: FORK Failed, errno = %d\n", errno); 
  } 
  return 0;
}
                                              
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by: nociPosted on 2009-11-06 at 05:14:08ID: 25758767

it's execv args:

execv("/bin/echo","echo","hello",NULL);                              // the trailing 0 is optional...

The first argument is the file, the next is argv[0]...
I'll try tonight, I have no linux at the current workplace.

 

by: kyleb84Posted on 2009-11-06 at 16:47:27ID: 25764399

According to LIBC:

 Function: int execv (const char *filename, char *const argv[])

 

by: nociPosted on 2009-11-07 at 07:42:33ID: 25766633

This works a little better...
execl works as intended.
Your fread only read 1 , 1 byte block, now it return 14 (the echo string + \n).

#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <unistd.h>
#include <errno.h>
#include <stdlib.h> 
#define PIPE_PARENT 0
#define PIPE_CHILD 1 
int main (int argc, char *argv[])
{ 
  int channels[2]; 
  char mbr[512]; 
  pipe(channels); 
  pid_t pid = fork(); 
  if (pid == 0) { 
    // Child process, close parent's end.
    close (channels[PIPE_PARENT]); 
    // Close STDOUT
    close(1); 
    // Duplicate the child channel to STDOUT
    dup2(channels[PIPE_CHILD], 1); 
    // Close our old channel fd
    close(channels[PIPE_CHILD]);
    // Execute a file, hopefully anything it prints to STDOUT shoots straight through
    // our channel[PIPE_CHILD]
    execl("/bin/echo","echo","Test message!",NULL);
    exit(100);
  } else if (pid > 0) {
    FILE *f;
    // Parent, close childs end.
    close(channels[PIPE_CHILD]);
    // Open the parent's end
    f = fdopen(channels[PIPE_PARENT], "r");
    if (f == NULL) {
      printf("ERROR: Failed to open channel PIPE_PARENT, errno = %d\n", errno);
    } else {
      // Should read the char 'T'...
      printf("fread(PIPE_PARENT): %d, errno = %d\n", (int) fread(&mbr, 1, 512, f), errno);
      fclose(f);
    }
    close(channels[PIPE_PARENT]);
  } else {
    // Failure
    printf("ERROR: FORK Failed, errno = %d\n", errno);
  }
  return 0;
}
                                              
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by: kyleb84Posted on 2009-11-10 at 00:06:32ID: 25783289

Work well, if your UID/GID = 0....

If I su to a test user, it doesn't work which is what I require...

For a little more insight into the project,

I'm running Apache/PHP, I really don't want the apache/php process to have root privileges since it makes security so much more complicated!

I require a php script to call an executable that outputs data in a pre-defined format (Readable from my php script), but that executable requires root privileges to read the mbr of any given disk...

This is why sudo cannot work (Apache/PHP has no tty environment, sudo requires one).

Hope the context allows you to give me an alternate solution since the above, tho close, does not give me what I need.

Cheers,

KB.

 

by: nociPosted on 2009-11-10 at 00:49:00ID: 25783472

THe program is one thing, the thing to make it work is:Assuming your printmbr is still  named the same and the tool you write to read one block from the first diskblock is called readmbr:

chown root:root readmbr              # make root owner
chmod ugo+x readmbr                  # make exec. for any one
chmod ugo-rw readmbr                 # remove write & read access
chmod u+s  readmbr                     # make setuid

Now the readmbr will run as root where your main program doesn't.

note NOT printmbr as you made it should run as root, but the '/bin/echo' part
only...

 

by: kyleb84Posted on 2009-11-10 at 01:04:59ID: 25783550

ls -l of directory contents:

-rw-r--r-- 1 root root  258 2009-11-05 11:36 Makefile
-rwxr-xr-x 1 root root 6323 2009-11-10 18:58 printmbr
-rw-r--r-- 1 root root 1380 2009-11-10 18:58 printmbr.c
-rw-r--r-- 1 root root 1932 2009-11-10 18:58 printmbr.o
-rws--x--x 1 root root 5494 2009-11-05 22:43 readmbr
-rw-r--r-- 1 root root  843 2009-11-05 22:43 readmbr.c
-rw-r--r-- 1 root root 1364 2009-11-05 22:43 readmbr.o

Output of ./printmbr as user 'test'

[test@localhost printmbr]$ ./printmbr
Cannot open /dev/sda
fread(PIPE_PARENT): 0, errno = 29
Value = 0
Result = ''
[test@localhost printmbr]$



Is there something I'm missing?
Do I need to setuid() within readmbr?

 

by: kyleb84Posted on 2009-11-10 at 01:28:53ID: 25783728

WORKING!!!


Added some seteuid() code to readmbr... Presto!


Many thanks noci, much appreaciated.

 

by: kyleb84Posted on 2009-11-10 at 01:29:27ID: 31649941

Exactly what I was after. Cheers.

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