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11.03.2006 at 06:42AM PST, ID: 22047952
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9.2

Cat, Grep, Variable and a list file

Asked by DarkHound in Unix Systems Programming

Tags: , ,

Ok here's the situation. I need to strip all lines from a long file which contain certain words. This list of words is ever-growing, and will probably stay that way. Currently I have a bash script that cats a file, then uses grep -v to strip that line, then it outputs it to another file after all the stripping is complete. At first it wasn't difficult, until I realised that I could only use so many instances of grep in a row before the script would break. So I was resolved to output it to another file and cat it again. I know there is an easier way to do this, I just don't know enough about shell scripting to figure it out.

Basicly what I want to have happen is I would like to maintain a separate file containing a list of words who's lines need to be stripped. I would then like the bash script to cat that file, grep for the variable and then output it to a new file with the words stripped.

Kinda like this.
cat filename.txt | grep -v $stripme > stripped.txt

I just don't know how to tell the script that $stripme is the contents of the stripme.txt file. The contents of the stripme.txt file can consist of 1 or more words, each on a new line. Example:
Item A
Bob
Snack Master Supreme
John


500 points for working code, and my thanks.
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[+][-]11.03.2006 at 06:56AM PST, ID: 17866805

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[+][-]11.03.2006 at 07:01AM PST, ID: 17866843

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[+][-]11.03.2006 at 07:49AM PST, ID: 17867296

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[+][-]11.03.2006 at 07:56AM PST, ID: 17867353

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[+][-]11.03.2006 at 08:20AM PST, ID: 17867607

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[+][-]11.03.2006 at 11:33AM PST, ID: 17869323

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About this solution

Zone: Unix Systems Programming
Tags: grep, variable, cat
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Solution Provided By: ozo
Participating Experts: 3
Solution Grade: A
 
 
[+][-]11.04.2006 at 06:48AM PST, ID: 17873406

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[+][-]11.06.2006 at 05:27AM PST, ID: 17880756

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