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05.31.2007 at 08:58AM PDT, ID: 22604968
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8.0

How to load standard output into an array using bash?

Asked by dongjinkim in Unix Systems Programming

Tags: , , ,

Hello experts,
I have 2 restrictions on a script I need to write.
I need to use bash shell.
I cannot generate temporary files due to permission settings on the file system.

Given those restrictions, is it possible for me to capture the standard output of a program (e.g. psql) and store each line in an array?
I know this is easily possible in korn shell, because I can simply use a pipe to direct the standard output into a loop that reads each line into the array:

INDEX=0
psql -c "select * from some_table' |
while read LINE
do
  DATA[$INDEX]=$LINE
  (( INDEX = INDEX + 1 ))
done

# the following line displays data in ksh but not bash
echo DATA=$DATA{*}

However, it seems that bash shell spawns a new shell every time a pipe is used. In this case, the while loop runs inside a different shell... the changes to the DATA array are lost once the while loop finishes, since the spawned shell is closed.

Does anyone have a solution for this problem?  (i.e. load each line of standard output into an array)Start Free Trial
[+][-]05.31.2007 at 12:16PM PDT, ID: 19190704

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[+][-]06.01.2007 at 08:26AM PDT, ID: 19195723

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[+][-]06.01.2007 at 03:36PM PDT, ID: 19198847

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About this solution

Zone: Unix Systems Programming
Tags: array, bash, output, load
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Solution Provided By: nixfreak
Participating Experts: 2
Solution Grade: A
 
 
 
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