I had meant to add this link:
http://en.wikipedia.org/wi
See towards the bottom under "normal approximation"
(°v°)
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Question
formula to calculate cummulative normal or binomial distribution
Hello experts
The formula
(N! / k!(n-k)!) (p^k) (q ^ (n-k)) give me exact probablity. So lets say that I have this
N = 106
k = 56
p = 0.6732
q = 1-p
it will give me exactly k out of N. What if I want k or fewer out of N? is there a formula for that?
How do we even calculate that
Thanks
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Answers
I think harfang has answer all the parts. Some little info to added :
In most cases, you may approximate binomial with normal. And to obtain the prob for "K or fewer", you may then use Normal CDF, which in terms you'll need another approximation.
A sample can be found here:
http://www.sitmo.com/doc/
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by: harfangPosted on 2009-10-27 at 17:55:20ID: 25679154
To get "k or fewer", you will need to sum probabilities:
Sum i=0; i=k { B(i, N, p) } | B is your formula
As this is computer intensive, for large values of N you usually approximate the cumulative B using a normal distribution.
(°v°)