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09.24.2007 at 09:50AM PDT, ID: 22848772
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8.0

DateDiffs Excel VBA increment a value of one after DateDiff is made Excel VBA

Asked by thomashospital in Access Coding/Macros, Miscellaneous Programming, Microsoft Excel Spreadsheet Software

Tags: , , ,

I am working on a piece of code that I obtained from my last question on this site.  Here is the code:
Function DateDiffs(EarlierDate As Date, LaterDate As Date, one as integer) As Long
'Returns the difference between two dates if they are from same month & year. _
         Otherwise, returns day of month for LaterDate. Returns 0 if either date is blank. _
         Function tolerates text input if it can be converted to a date.
Dim dat As Date

DateDiffs = Int(LaterDate) - Int(EarlierDate)
If Month(EarlierDate) <> Month(LaterDate) Or Year(EarlierDate) <> Year(LaterDate) Then DateDiffs = Day(LaterDate)
If Month(EarlierDate) = Month(LaterDate) And Year(EarlierDate) = Year(LaterDate) And Day(EarlierDate) = Day(LaterDate) Then DateDiffs = 1
If EarlierDate * LaterDate = 0 Then DateDiffs = 0
End Function

I need this piece of code to add a value of 1 or increment 1 automatically:
DateDiffs = Int(LaterDate) - Int(EarlierDate)

And I need this piece of code to add a value of 1 or increment 1 automatically:
If Month(EarlierDate) <> Month(LaterDate) Or Year(EarlierDate) <> Year(LaterDate) Then DateDiffs = Day(LaterDate)
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[+][-]09.24.2007 at 12:41PM PDT, ID: 19951139

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About this solution

Zones: Access Coding/Macros, Miscellaneous Programming, Microsoft Excel Spreadsheet Software
Tags: excel, vba, increment, datediff
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Solution Provided By: byundt
Participating Experts: 1
Solution Grade: A
 
 
[+][-]09.24.2007 at 01:05PM PDT, ID: 19951336

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