Advertisement

09.15.2008 at 05:44PM PDT, ID: 23733768
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

9.3

VBA Error Returning Value

Asked by IEHP1 in Access Coding/Macros, VB Database Programming

Tags: , , ,

hi experts,

I have a function to extract information from a field.
However, some of the data does not contain the char i am looking for in the field.
Hence, i receive error in these records.

I am wondering if anyone  can help me to modify the code attached so that when there is an error, the function will return a null value for that record?

Thanks!
Start Free Trial
1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
Function GetREF(pvarIn)
 
    Dim intEnd As Integer
    
    If (IsNull(pvarIn) Or pvarIn = "") Then
        GetREF = Null
    Else
        intEnd = InStr(1, pvarIn, "(oc:")
        GetREF = Mid(pvarIn, 1, intEnd - 1)
    End If
    
End Function
[+][-]09.15.2008 at 07:38PM PDT, ID: 22484435

View this solution now by starting your 7-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zones: Access Coding/Macros, VB Database Programming
Tags: MS, Access, 2000, VBA Error Returning Value
Sign Up Now!
Solution Provided By: kelvinsparks
Participating Experts: 1
Solution Grade: A
 
 
 
Loading Advertisement...
20080716-EE-VQP-32 / EE_QW_2_20070628