Question

Sending XML via HTTP POST

Asked by: dedpc

Dear Experts

I have a problem here where I'm supposed to send some XML Data to a remote server hosting a JSP page that accepts the XML. The data should be sent via HTTP POST along with a security key attribute.

For example, if the URL is https://www.jsppage.com/acceptingpage.jsp, the POST is made with the following attributes:

key = hi773jHJkd
xml = the xml data

The JSP page returns 1 if successful and 0 if not.

If someone's done similar stuff before, could you please help with some tips or sample code in C# about how to get this done?

Please note that the JSP page was created by someone else and I haven't the slightest clue about it except that it accepts my data and security key and returns 1 or 0.

Thanks, any help will be much appreciated.

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Asked On
2009-01-27 at 02:33:01ID24086438
Tags

XML C# ASP.NET

Topics

Internet File Sharing Software

,

Networking Protocols

,

Java Server Pages (JSP)

,

.NET

,

Microsoft Visual C#.Net

Participating Experts
2
Points
500
Comments
7

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Answers

 

by: KuldeepchaturvediPosted on 2009-01-29 at 05:23:11ID: 23496874

See if this helps..

http://geekswithblogs.net/rakker/archive/2006/04/21/76044.aspx

Basically for XML you can have the XML in a string and then pass it as parameter..

 

by: dedpcPosted on 2009-01-29 at 06:40:29ID: 23497782

Hi Kuldeep, I've tried streaming my data as UTF8 and ASCII encoded bytes like the link says but I keep returning 0. This is my code below.

string strKey = "mykey";
                string strXML = this.GetTextFromXMLFile(fileLoc);
                Uri httpsURI = new Uri("https://www.jsppage.com/jspPage.jsp");

                ASCIIEncoding encoding = new ASCIIEncoding();
                string postData = "key=" + strKey;
                postData += ("&xml=" + strXML);
                byte[] data = encoding.GetBytes(postData);
                // Prepare web request...
                //HttpWebRequest myRequest =
                //  (HttpWebRequest)WebRequest.Create(httpsURI);
                WebRequest myRequest = WebRequest.Create(httpsURI + "?" + postData);

                myRequest.Method = "POST";
                myRequest.ContentType = "application/x-www-form-urlencoded";
                myRequest.ContentLength = postData.Length;
                Stream RequestStream = myRequest.GetRequestStream();
                // Send the data.
                RequestStream.Write(data, 0, data.Length);
                RequestStream.Close();

                WebResponse AMAResponse = myRequest.GetResponse();

                string serverResponse = "";
                Stream responseStream = AMAResponse.GetResponseStream();
                StreamReader sr = new StreamReader(responseStream);
                serverResponse = sr.ReadToEnd();
                ret = serverResponse.Trim();

 

by: KuldeepchaturvediPosted on 2009-01-29 at 07:21:06ID: 23498257

Do you have control over that jsp page?
i.e. if you want can you put debug statements/sourcecode your your jsp here?

 

by: shivaspkPosted on 2009-01-30 at 01:12:31ID: 23506319

change
myRequest.ContentType = "application/x-www-form-urlencoded";

to

myRequest.ContentType = "text/xml";

and try.

Also can you provide the WSDL location?

 

by: shivaspkPosted on 2009-01-30 at 01:13:50ID: 23506326

Oh sorry i though it was a web service request. just try my first suggestion.

20120131-EE-VQP-002

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