Thank you for giving a good picture of the Infpoath in few lines. It's worth for guys like me who are completely new to Infopath. Once again thanks.
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Browse All TopicsI have designed a Infopath 2003 form Test.xsn and published at a shared folder(D:\Info\Test.xsn). I opened the form and saved it as Test.xml. Copied the Test.xml from local machine to my laptop which is stand alone. When am trying to open the Test.xml file, getting the following error message.
Infopath cannot open the following file test.xml.
It is looking for the path(shared folder - D:\Info\Test.xsn)..
Can someone help me out with this...
Thanks in advance
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by: clayfoxPosted on 2009-09-15 at 15:34:37ID: 25340314
Here is how InfoPath works.
It has two components, the data (xml file) and the template (xsn file)
If you look at the xml form in Notepad, you will see that it is just the data, the template has the logic and layout of the form.
So in the header of each xml file is a link to the published location of the template, so that InfoPath knows how to render the xml data.
Therefore you cannot open an XML file in InfoPath if InfoPath cannot access the template.
So you should publish the template to a network location, web server (like SharePoint), or to Outlook (and use email) to distibute your forms.