selecting a childNode by attribute and looping through all of it's childNodes to create an array

selecting a childNode by attribute and looping through all of it's childNodes to create an array
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Question: Hello All,
Please help, I'm trying to select a childNode by attribute and looping through all of it's childNodes to create an array.
This is the stripped down skeleton of the XML.

So I want to build an array from the childNodes of the page with the id="extLinks"
This cannot be an absolute reference since many <page> nodes may be added and the node could be anywhere within the XML doc.

==========================
xml
==========================
<?xml version="1.0" encoding="utf-8"?>
<site>
      <tracking embed/>
      <country codes/>
      <pages>
            <page id="page1">
            </page>
            <page id="page2" >
            </page>      
            <page id="extlinks">
                  <link sLink="http://www.msn.com"/>
                  <link sLink="http://www.google.com"/>
                  <link sLink="http://www.yahoo.com"/>
            </page>
      </pages>
</site>
===============================
broken AS
This is where I am at and it is becoming a jumble.
===============================
extLinkList.onLoad = function(success) {
      //trace(extLinkList);
      var linkArray:Array = new Array();
      for (m=0; m<3; m++) {
            var sLink:String;
            var xmlNodeBase:XMLNode = extLinkList.childNodes[0].childNodes[2].childNodes;
            var xmlNodeBasePlus = xmlNodeBase.childNodes[m];
            if (xmlNodeBase.attributes.id == "extLinks") {
            xmlNodeBasePlus=xmlNodeBase.childNodes[m]
            sLink = xmlNodeBasePlus.attributes.sLink;
            linkArray.push(sLink);
            }
      }
      extLink1 = linkArray[0];
      extLink2 = linkArray[1];
      extLink3 = linkArray[2];
      trace(linkArray);
};
================================

This returns nothing, I am assuming that it is not finding anything because the if loop is never entered.

Thanks for all your input.