Question

Working Out UK Tax Weeks & Months

Asked by: jturkington

Trying To Find A CF Function To Work Out UK (Tax Week & Tax Month) For A Specified Date

Definations Of a Tax Week & Tax Month:  -

Income tax weeks (tax weeks)

Tax weeks are periods of seven days which follow on from each other starting on 6 April each year. The first tax week is 6-12 April inclusive, the second tax week 13-19 April inclusive, and so on.

The odd day or days at the end of the last complete tax week in the year (5 April or in leap years 4 and 5 April) are treated as a whole tax week, that is tax week 53.

Income tax months (tax months)

Income tax months are periods following on from each other in an income tax year. They start on the 6th of one month and finish on the 5th of the following month. The first income tax month is 6 April - 5 May inclusive, the second income tax month is 6 May - 5 June inclusive, and so on.

Cheers

JT

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Asked On
2006-01-26 at 07:17:20ID21711268
Tags

tax

,

weeks

Topic

ColdFusion Application Server

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    Answers

     

    by: jturkingtonPosted on 2006-01-26 at 07:40:24ID: 15796028

    I have found a bit of code in Javascript that could work works by passing in (year, month, date)

    function UKtaxWNstr(y, m, d) { var dd, fy = y // m = 1..12
      if (m*32+d<134) fy--
      dd = (Date.UTC(y, m-1, d) - Date.UTC(fy, 3, 6))/864e5
      return 'UK Revenue & Customs:' + ' Year ' + fy + ' week ' +
        LZ(Math.floor(dd/7)+1) + ' day ' + (dd%7+1) + ';' }

    function UKtaxMNstr(y, m, d) { var yy = y, mm = m // m = 1..12
      if (d<6) mm--
      if (mm<4) { yy-- ; mm += 12 }
      return ' Year ' + yy + ' month ' + LZ(mm-3) + '.' }

    These functions can easily be generalised for Month 1 and Week 1 starting on any date of the calendar year; in the code, 134 is just 4*32+6 for Month 4 Day 6.

    Any help to convert this to a cfscript/cfc would be much appreciated !

    Cheers

    JT

     

    by: jturkingtonPosted on 2006-01-26 at 08:23:55ID: 15796494

    Sorry Javascript function is

    <script>
    function LZ(x) { return (x<0||x>=10?"":"0") + x }

    function UKtaxWNstr(y, m, d) { var dd, fy = y // m = 1..12
      if (m*32+d<134) fy--
      dd = (Date.UTC(y, m-1, d) - Date.UTC(fy, 3, 6))/864e5
      return 'UK Revenue & Customs:' + ' Year ' + fy + ' week ' +
        LZ(Math.floor(dd/7)+1) + ' day ' + (dd%7+1) + ';' }

    function UKtaxMNstr(y, m, d) { var yy = y, mm = m // m = 1..12
      if (d<6) mm--
      if (mm<4) { yy-- ; mm += 12 }
      return ' Year ' + yy + ' month ' + LZ(mm-3) + '.' }
     
      function TaxTest() { var D = new Date(),
      dy = D.getDate(), mo = D.getMonth()+1, yr = D.getFullYear()
      document.write('By TaxTest() : Today is ', D.YMDDstr(),
        ' ; thus it is :\n', UKtaxWNstr(yr, mo, dy),
        UKtaxMNstr(yr, mo, dy), '\nOddWkNo3(D, 4, 6) : ',
        ywkdStr(D=OddWkNo3(new Date(yr, mo-1, dy), 4, 6)),
        ";  OffWkNo3 : ", OffWkNo3(D, 4, 6).ISOlocaldateStr()  ) }
          
          
    </script>

     

    by: mrichmonPosted on 2006-01-26 at 09:59:14ID: 15797549

    So are you looking for how to convert to CF or is the javascript code sufficient?

     

    by: jturkingtonPosted on 2006-01-26 at 10:24:38ID: 15797828

    Yes i need to convert it to CF

     

    by: mrichmonPosted on 2006-01-26 at 11:10:04ID: 15798279

    Okay.

    The way I would do it is using a cfc so you can preserve the smaller functions in the javascript block.

    For example, the first one would look like

    <cffunction name="LX">
       <cfargument name="x" type="numeric" required="true">
       <cfif x LT 0 OR x GTE 10>
            <cfset returnvalue = x>
       <cfelse>
           <cfset returnvalue = "0" + x>
        </cfif>
       <cfreturn returnvalue>
    </cffunction>

    However, the logic of that javascript doesn't really make sense to me.... but that is the direct conversion....

    Then it would be called as :

    <cfinvoke component="YourCFCName" method="LX" x="#variableGoesHere#" returnVariable="yourReturnVariable">
    </cfinvoke>

     

    by: jturkingtonPosted on 2006-01-29 at 04:20:30ID: 15817050

    Thanks mrichmon,  still having a few problems trying to work out the logic in CF to achieve the Tax Week & Tax Month ??

    JT

     

    by: mrichmonPosted on 2006-01-30 at 08:39:25ID: 15824949

    Okay I can help with that, but part that CANNOT be done is the document.write.  That is client side and CF is server side.

    What do you want it to do instead?

     

    by: jturkingtonPosted on 2006-01-30 at 09:13:49ID: 15825304

    mrichmon all i want to do is to have some type of formula that will determine the startdate and endate of a UK Tax week given a specified date. and store it in an array etc...

    For Example trailblazzyr55 kindly helped me with a similar question

     http://www.experts-exchange.com/Web/WebDevSoftware/ColdFusion/Q_21684880.html

    Cheers

    JT

     

    by: mrichmonPosted on 2006-01-30 at 11:14:29ID: 15826488

    Basically what you need to do is to look at each function and slowly convert to CF one line at a time.

    For example:

    function UKtaxWNstr(y, m, d) { var dd, fy = y // m = 1..12
      if (m*32+d<134) fy--
      dd = (Date.UTC(y, m-1, d) - Date.UTC(fy, 3, 6))/864e5
      return 'UK Revenue & Customs:' + ' Year ' + fy + ' week ' +
        LZ(Math.floor(dd/7)+1) + ' day ' + (dd%7+1) + ';' }

    First declare the function with the same name:
    <cffunction name="UKtaxWNstr">

    Next the incoming variables:
       <cfargument name="y" type="numeric" required="true">
       <cfargument name="m" type="numeric" required="true">
       <cfargument name="d" type="numeric" required="true">

    Then the first line
    <cfset fy = y>
    Next line:
    <cfif (m*32 + d) LT 134>
       <cfset fy = fy - 1>
    </cfif>
    etc.

    If you run into a javascript function you don't know it is eady to see what it is doing on the web like the UTC function - here is a link:
    http://www.devguru.com/Technologies/ecmascript/quickref/date.html
    WHere it says:
    UTC Method
    This method returns the number of milliseconds from the date in a Date object since January 1, 1970 00:00:00 according to universal time. This is a static method of Date so the format is always Date.UTC() as opposed to objectName.UTC().

    Syntax: Date.UTC(year, month, day [, hours, minutes, seconds, ms])

    SO slowly working through will get the function converted.

     

    by: trailblazzyr55Posted on 2006-02-01 at 17:40:47ID: 15849776

    jturkington,

    this isn't a direct conversion from the javascript above, but it's what you're looking for I think...

    having these two functions, you can try and put them into cffunctions and let me know if you need any help, these are done in cfscript.

    you can either take what I have here and convert them to cffunctions for use in a CFC or include these functions in a cffunction and use them in a CFC, it's up to you. They follow the same idea as the last ones I did... let me know if you want to explain anything or if you need help...

    here's the cfscript version...
    ---------------------------------

    <cfscript>
    function getTaxWeek(d,m,y){
          od=createdate(y,m,d);
          if(datecompare(createdate(y,m,d),createdate(y,4,6)) eq -1){y=decrementvalue(y);}
          sd=createdate(y,4,6);
          md=dateadd('d',6,sd);
          dayArray=arrayNew(2);
          for(i=1;i lte 52;i=i+1){
                dayArray[i][1]=sd;
                dayArray[i][2]=md;
                sd=dateadd('d',7,sd);
                md=dateadd('d',7,md);
          }
          dayArray[53][1]=sd;
          dayArray[53][2]=dateadd('d',datediff('d',sd,createdate(datepart('yyyy',sd),4,5)),sd);
          DateOutput=structnew();
          for(i=1;i lte arraylen(dayArray);i=i+1){
                t1=datecompare(dayArray[i][1],od);
                t2=datecompare(dayArray[i][2],od);
                if( (t1 eq -1 and t2 eq 1) or (t1 eq 0) or (t2 eq 0) ){
                      DateOutput.w=i;
                      DateOutput.y=y;
                      break;
                }
          }
          return DateOutput;
    }

    function getTaxMonth(d,m,y){
          od=createdate(y,m,d);
          if(datecompare(createdate(y,m,d),createdate(y,4,6)) eq -1){y=decrementvalue(y);}
          m1=4;m2=5;y1=y;y2=y;
          sd=createdate(y,m1,6);
          md=createdate(y,m2,5);
          monthArray=Arraynew(2);
          for(i=1;i lte 12;i=i+1){
                monthArray[i][1]=sd;
                monthArray[i][2]=md;
                m1=m1+1;m2=m2+1;
                if(m2 gt 12){m2=1;y2=y2+1;}if(m1 gt 12){m1=1;y1=y1+1;}
                sd=createdate(y1,m1,6);
                md=createdate(y2,m2,5);            
          }
          MonthOutput=structnew();
          for(i=1;i lte arraylen(monthArray);i=i+1){
                t1=datecompare(monthArray[i][1],od);
                t2=datecompare(monthArray[i][2],od);
                if( (t1 eq -1 and t2 eq 1) or (t1 eq 0) or (t2 eq 0) ){
                      MonthOutput.m=i;
                      MonthOutput.y=y;
                      break;
                }
          }      
          return MonthOutput;
    }
    </cfscript>

    <cfdump var="#getTaxMonth(6,3,2006)#">
    <cfdump var="#getTaxWeek(6,3,2006)#">
    <!---/ format is: function(day/month/year) /--->
    -----------------------

    'y' on the output is the fiscal year, not inputed year in some cases...

    you can also output them like so..

    <cfoutput>#getTaxMonth(6,3,2006).m#</cfoutput> //month number
    <cfoutput>#getTaxMonth(6,3,2006).y#</cfoutput>  //fiscal year

    <cfoutput>#getTaxMonth(6,3,2006).w#</cfoutput> //week number
    <cfoutput>#getTaxMonth(6,3,2006).y#</cfoutput> //fiscal year

    regards,
    ~trail

     

    by: trailblazzyr55Posted on 2006-02-27 at 11:36:52ID: 16058113

    jturkington, the last post I made does what you're looking to do, let me know if you need any more help...

     

    by: jturkingtonPosted on 2006-02-28 at 00:13:51ID: 16062928

    Ahh sorry trailblazzyr55 thought i had closed this question....

    yes the last post did the trick thanks again trailblazzyr55

    ;-)

    JT

     

    by: trailblazzyr55Posted on 2006-02-28 at 08:16:16ID: 16066545

    You're welcome, glad I could help =)

    Thanks,
    ~trail

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