you could aslo use reFind or refindNoCase which use regular expressions
reFind(reg_expression, string)
refind("jobs\.(old|new)", string)
Main Topics
Browse All Topics
hi
how can i test if a string contains another string? for example, if i need to return true if a passed string is "jobs.new" or "jobs.old", it would make sense just to check for the existance of "jobs." in the passed string. how would i do that?
many thanks
This Question has been solved and asker verified All Experts Exchange premium technology solutions are available to subscription members.
Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.
If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.
Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.
Access the answers to your technology questions today.
30-day free trial. Register in 60 seconds.
Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Try it out and discover for yourself.
30-day free trial. Register in 60 seconds.
Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.
Jester is right, FindNoCase works well.
Just wanted to add CONTAINS can do it as well..
<cfif variables.mystring CONTAINS "jobs">
There is also DOES NOT CONTAIN
<cfif variables.myString DOES NOT CONTAIN variables.substring>
CONTAINS does a string comparison (even if numbers). So...
123.456 CONTAINS 3.4 would be TRUE
a-ha with MX, take it a step further!! (unleash the java inside you!!)
http://www.activsoftware.c
Some useful methods
Return Type Method Signiture Description
String string.substring(int position) returns the substring starting at position, zero based
String string.substring(int position, int length) returns the substring length characters long starting at position, zero based
int string.indexOf(string substring) returns a zero based index to of where substring occurrs in string
int string.indexOf(string substring, int startPosition) returns a zero based index to of where substring occurrs in string starting at startPosition
boolean string.startsWith(String substring) true if the string starts with substring
boolean string.endsWith(String substring) true if the string ends with substring
char string.charAt(int pos) returns the character at a specified position
Business Accounts
Answer for Membership
by: Jester_48Posted on 2006-08-04 at 09:15:19ID: 17251152
you could use find
Find(substring, string)
or
findNoCase(substring, string) for a case insensitive search