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12.26.2004 at 10:43AM PST, ID: 21253990

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8.3

javax.servlet.HttpServletRequest cannot be resolved

Zone: Java Server Pages (JSP)

Tags: jar, cannot, resolved

I am writing a class in eclipse. I want one of the contructors to take a single argument, a reference to a javax.servlet.HttpServletRequest object. typing

public classname(javax.servlet.HttpServletRequest request){
}

tells me that javax.servlet.HttpServletRequest cannot be resolved. I also cannot import javax.servlet.* . Do I need to somehow 'reference' a special jar file in my project?

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Question Stats

Zone: Programming

Question Asked By: dbyrne03

Solution Provided By: tbone343

Participating Experts: 5

Solution Grade: A

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12.26.2004 at 10:58AM PST, ID: 12903778

Rank: Master

ldbkutty:

Add:

import javax.servlet.http.HttpServletRequest;

PS: Add J2EE library container to your project build path.

and do

public ClassName(HttpServletRequest request) {
}

12.26.2004 at 11:21AM PST, ID: 12903827

Rank: Genius

bloodredsun:

>>PS: Add J2EE library container to your project build path.

called J2EE.jar, then most recent version of which is 1.4. and cann be found here http://java.sun.com/j2ee/1.4/download.html#sdk

12.26.2004 at 11:36AM PST, ID: 12903864

tbone343:

If you are using the latest Tomcat, look for \tomcat\common\lib\servlet-api.jar and add that to the classpath. If you are using another servlet container, it is often called "servlet.jar".

Accepted Solution

12.26.2004 at 05:04PM PST, ID: 12904562

dbyrne03:

I found servlet-api.jar in an old jboss installation dir. I placed it under "C:\Program Files\eclipse\servlet-api.jar", right clicked on my project -> Properties and added it via the Libraries tab. It works now, but how does this change the classpath? It sure doesn't change the classpath used when eclipse is fired up, right? Also, I'm not too thrilled about the path of servlet-api.jar (see above), can you tell me what might be a more apropriate path?

12.26.2004 at 05:42PM PST, ID: 12904621

tbone343:

This jar file just contains a bunch of class files. By adding it to your project libraries, you are putting it on the classpath (that is, when you use certain classes in your code, it will search through everything in your project's libraries). You can simply cut and paste this jar using windows explorer and put it anywhere you want first and then add it to your libraries tab if that is what you prefer.

12.26.2004 at 05:43PM PST, ID: 12904622

Rank: Master

ldbkutty:

>> I'm not too thrilled about the path of servlet-api.jar (see above), can you tell me what might be a more apropriate path?

(1) Place all your general "JAR" files like javax.servlet.jar, mail,jar, etc.. (including your app. server JAR's) in a general folder. (say, C:\Program Files\eclipse\mylibs ).

(2) In your Eclipse, Window->Preference->Java->Build Path->Classpath Variables, give that path with name, say MYECLIPSE_LIB_HOME.

So, for example if you are creating a new project with the above program, but didn't included the MYECLIPSE_LIB_HOME in your Java Build Path-Libraries. On writing:

public ClassName(HttpServletRequest request) {
}

Your eclipse auto-debugger(!) will ask you to load the PATH which you have already defined in your Classpath Variables.

12.27.2004 at 02:43PM PST, ID: 12909373

raj3060:

Did you try control + shift + O to load libraries automatically. If not try it.

04.09.2005 at 11:05AM PDT, ID: 13744389

patbin:

add servlet.jar to your project build path

20080236-EE-VQP-29