PHP Upload image

Quick example

<form name="file_upload" method="post" action="process.php" enctype="multipart/form-data">
<input type="hidden" name="MAX_FILE_SIZE" value="1000000" />
<input type="file" name="form_image" />
</form>


----------------

<?php

if(is_uploaded_file($_FILES['form_image']['tmp_name']))
{
  // file uploaded to server
  echo "file information is :-<br />";
  print_r($_FILES);

      $imageInfo = getimagesize($_FILES['form_image']['tmp_name']);
      $width = $imageInfo[0];
      $height = $imageInfo[1];
      $image_type = $imageInfo[2];
      print_r($imageInfo );

  // move_uploaded_file($_FILES['form_image']['tmp_name'], "./tempfile/".$_FILES['form_image']['tmp_name']);

}
else
{
  // file not uploaded to server
}

the move_uploaded_file was supposed to have ['name'];  at the end not ['tmp_name'];

Hi waygood,

Your example has proved to be a great help. However, I have some more problems.

1. When I tried to insert the $imageInfo into my table, it shows "array" instead of the name of my file (e.g. image.jpg).

2. I have a textarea for the posting of the image description. But I haven't been able to grab the description and insert it into the gallery table.

I would appreciate anyone's help.

--- Table ---
Gallery table has 3 fields:
id(primary key)
image(for the uploading of image file)
imageDescription(a description for the image file)

--- gallery_upload form ---
<form action="gallery_insert.php" method="post" enctype="multipart/form-data">
  <p>Note: All fields are mandatory / compulsory. Please fill them all up.
  </p>
  <p>Description:<br>
    <textarea name="imageDescription" rows=4 cols=70></textarea>
  </p>
  <p>Upload a photo(gif/jpeg format) for this event: <br>
    <input type="hidden" name="MAX_FILE_SIZE" value="1000000">
    <input name="image" type="file" size="70">
  </p>
  <p>
    <input type="submit" value="Send this file!">
  </p>
</form>

--- gallery_insert.php ---
if(is_uploaded_file($_FILES['image']['tmp_name']))
{
  // file uploaded to server
  echo "file information is :-<br />";
  print_r($_FILES);

     $imageInfo = getimagesize($_FILES['image']['tmp_name']);
     $width = $imageInfo[0];
     $height = $imageInfo[1];
     $image_type = $imageInfo[2];
     print_r($imageInfo);

  move_uploaded_file($_FILES['form_image']['tmp_name'], "./tempfile/".$_FILES['form_image']['name']);

//Insert record into database
$insert_data = "INSERT INTO gallery VALUE
                      ('', '$imageInfo' , '$imageDescription')";
}
else
{
      echo "No image was uploaded!";
}      
            
if (mysql_query($insert_data,$db)) {
echo "Record added";
}
else {
echo "No record was added";
}

as you can see from the code

     $width = $imageInfo[0];
     $height = $imageInfo[1];
     $image_type = $imageInfo[2];
     
$imageInfo IS an array, you need to specify which elements you want, when doing your insert.

e.g.
$insert_data = "INSERT INTO gallery VALUE
                      ('', '".$imageInfo[3]."' , '$imageDescription')";
NB I always seperate the variables from the text as there is a problem with array elements when doing it your way.    $text="text".$var[0]."text";

print_r($imageInfo);  will show your the array structure and the info it contains

imageInfo contains information relating to an image ie size and type, because you use the function getimagesize to gather it.
The file information can be found within $_FILES

getimagesize
---------------
Returns an array with 4 elements.
Index 0 contains the width of the image in pixels.
Index 1 contains the height.
Index 2 is a flag indicating the type of the image: 1 = GIF, 2 = JPG, 3 = PNG, 4 = SWF, 5 = PSD, 6 = BMP, 7 = TIFF(intel byte order), 8 = TIFF(motorola byte order), 9 = JPC, 10 = JP2, 11 = JPX, 12 = JB2, 13 = SWC, 14 = IFF, 15 = WBMP, 16 = XBM. These values correspond to the IMAGETYPE constants that were added in PHP 4.3.
Index 3 is a text string with the correct height="yyy" width="xxx" string that can be used directly in an IMG tag.

$_FILES
---------
$_FILES['userfile']['name']  The original name of the file on the client machine.
$_FILES['userfile']['type']  The mime type of the file, if the browser provided this information. An example would be "image/gif".
$_FILES['userfile']['size']  The size, in bytes, of the uploaded file.
$_FILES['userfile']['tmp_name']  The temporary filename of the file in which the uploaded file was stored on the server.
$_FILES['userfile']['error']  The error code associated with this file upload. ['error'] was added in PHP 4.2.0

from my first comment (adjusted a little):-
 move_uploaded_file($_FILES['form_image']['tmp_name'], "./upload_dir/".$_FILES['form_image']['name']);

where the directory 'upload_dir' is in the current directory where your script id being run.
moves the uploaded file (which is stored under a temp name to prevent over-writing other peoples) from the temp directory where all uploads are temporary stored to your directory (upload_dir) and renamed to the original name.

$insert_data = "INSERT INTO gallery VALUE
                      ('', '$imageInfo' , '$imageDescription')";
should be

$insert_data="INSERT INTO gallery VALUES ('', '".$_FILES['image']['name']."', '".$_POST['imageDescription']."')";

to display an image on a web page you need to use img, echo will just send the info to the page.

echo '<img src="'.$image.'" />';

If you store the image info index3 then you will have the dimensions.

$image=mysql_fetch_assoc($get_image_result);
echo '<img src="'.$image['name'].'" '.$image['dimensions'].' />';

this will give you something like <img src="a.gif" width="120" height="342" />