funny... but i only get 382 days...
anyways...
TheTime=DateDiff("y",Now,"
response.write TheTime
Let me know...
MaxOvrdrv2
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Question
Formatting <%DateDiff%>
Hi, guys
I'm using DateDiff method to count days...........
<%=DateDiff("d", Now, "04/08/02 00:00:00")*-1%>
... that displays number of days past since 04/08/02.....
Anyone know how to format it to show 1 year 3 moths 3 days instead of something like 456 days.....?
Any ideas are welcome:)
Cheers,
Kouras.
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Answers
MaxOvrdrv2
.....I didn't count like you:))
....Look you've got last chance:)
Luke's code is working.....your one is not , but coz your one is much shorter( dunno bout the size of script comparing to Luke's though), that's why I thought I'll wait a bit more, not long though:))
Thanx Luke, I will accept your answer in an hour if nothing else will be available.
Thanx, guys,
Kouras.
BTW: here's all my source for testing it
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=windows-1252" x-undefined>
<meta name="GENERATOR" content="Microsoft FrontPage 5.0">
<meta name="ProgId" content="FrontPage.Editor.
</head>
<body>
<form method = post action = test.asp>
StartDT:
<INPUT type="text" id=txt1 name=txt1><BR>
EndDT:
<INPUT type="text" id=txt2 name=txt2><BR>
<BR>
<INPUT type="submit" value="Submit" id=submit1 name=submit1>
<%
If Request.Form("txt1") <> "" and Request.form("txt2") <> "" then
Response.write(YearsMonths
end if%>
<%
Function YearsMonthsDays(StartDate,
'Written by Luke A. Davis
'Please, if you use or distrubute this code,
'please leave comment block in
Years =DateDiff("yyyy", StartDate, enddate)
StartDate=dateadd("yyyy",y
Months=DateDiff("M", startDate, EndDate)
StartDate=dateadd("M", Months, StartDate)
Days=DateDiff("d", StartDate, EndDate)
YearsMonthsDays = Years & "Year(s) " & Months & " Month(s) " & Days & " Day(s)"
End Function
%>
</form>
</body>
</html>
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by: luke_davisPosted on 2003-04-25 at 11:56:42ID: 8397442
Just wrote this function... call it insteqad of datediff.
<%=YearsMonthsDays("04/08/
<%
Function YearsMonthsDays(StartDate,
'Written by Luke A. Davis
'Please, if you use or distrubute this code,
'please leave comment block in
Years =DateDiff("yyyy", StartDate, enddate)
StartDate=dateadd("yyyy",y
Months=DateDiff("M", startDate, EndDate)
StartDate=dateadd("M", Months, StartDate)
Days=DateDiff("d", StartDate, EndDate)
YearsMonthsDays = Years & "Year(s) " & Months & " Month(s) " & Days & " Day(s)"
End Function
%>