Question

Convert string to number using VB / VBScript

Asked by: Mckenzma

I'm trying to create a serialized identification string, where the first 4 characters are letters and the last 5 characters are numbers.  To create a new ID, I get the maximum ID string from the database, extract the final 5 characters (which are in the form 00001, 00002, etc.), convert them to a number, add 1, and re-build a 9-character string using the new number.  My problem lies in converting the characters to a number; val() doesn't work and cint() requires a number input (I've tried it here and it doesn't work).  Is there a way to convert a string to a number value in VB Script?

Here's my code:

   strSQL = "Select max(ID) as Alumni_ID from RUNNERS.Ath_Profile where ID like " & CHR(39) & "Alum%" & CHR(39)  
   Set AlumData = nothing
   Set AlumData = Currdb.CreateDynaset(strSQL,4)
   AlumData.MoveFirst
   MaxAlumID = AlumData.Fields("Alumni_ID")
   If IsNull(MaxAlumID) Then
     AlumSeqNum = 1 'This covers the first record inserted to the database
   Else
     AlumSeqNum = Val(Right(CStr(MaxAlumID)), 5) + 1 'This is the command that fails.
   End If
   vAlumSerial = "0000" & Trim(CStr(AlumSeqNum))
   vAlumSSO = "Alum" & Right(vAlumSerial, 5) 'Re-build ID string with new serial number

Any help would be greatly appreciated, thanks!

mckenzma

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Asked On
2003-05-08 at 11:26:09ID20610293
Tags

vbscript

,

string

,

convert

,

number

Topic

Active Server Pages (ASP)

Participating Experts
4
Points
100
Comments
10

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Answers

 

by: fritz_the_blankPosted on 2003-05-08 at 11:29:49ID: 8490894

CInt() will convert the string to an integer.

Fritz the Blank

 

by: fritz_the_blankPosted on 2003-05-08 at 11:30:11ID: 8490895

CDbl() will convert the string to a numeric.

Fritz the Blank

 

by: fritz_the_blankPosted on 2003-05-08 at 11:31:15ID: 8490900

Cint(Right(CStr(MaxAlumID)),5)

should probably work in this case.

Fritz the Blank

 

by: msicePosted on 2003-05-08 at 11:31:56ID: 8490901

you coud use repalce to replace a number for a given character then cint()

 

by: MckenzmaPosted on 2003-05-08 at 17:27:55ID: 8492636

CInt does work... but my problem was having the parenthesis in the wrong place.  Correct expression should be Cint(Right(CStr(MaxAlumID),5)).  Thanks!

 

by: fritz_the_blankPosted on 2003-05-08 at 19:12:56ID: 8492970

Glad to have helped, any reason for the grade of B?

Fritz the Blank

 

by: MckenzmaPosted on 2003-05-09 at 18:39:33ID: 8498068

FTB,

Your answer was good... but included the same syntax error that caused my problem in the first place. So I didn't feel it warranted an "excellent" grade.  No hard feelings, I hope.

McKenzma

 

by: fritz_the_blankPosted on 2003-05-10 at 05:23:13ID: 8499777

No not at all, I missed that.

Fritz the Blank

 

by: devariojPosted on 2008-10-07 at 14:00:56ID: 22663756

One thing to note, CINT seems to always send an overflow error...rule of thumb for me has been to use CDBL

 

by: PasserbyPosted on 2009-09-01 at 17:25:35ID: 25237340

CLNG seems the better choice (never use short integers).

20120131-EE-VQP-002

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