Question

Comparing two strings

Asked by: humer2000

hi experts

I have the following code to compare two string
in fact i have two strings stored in the db
one is encrypted, the other is not encrypted

i am comparing decrypted value of the encrypted one with the other string and display a message accordingly

Sub ValidateCoupon (rc, msg)
dim EncodedName, DecodedName, Realname
EncodedName=couponname
DecodedName= Base64decode(EncodedName)
Realname = couponother

response.write "realname = <br>" & DecodedName & "<br>"
response.write "couponother = <br>" & Realname

if ucase(DecodedName) <> ucase(Realname) then
     msg= "Bad coupon name"
     rc=4
     exit sub
end if
end sub

OK now my problem it that when i compare decodedname and realname,
i get the result  "Bad coupon name" even if they are equal

My response.write shows that decodedname and realname are the same.

What the problem ?
Thx


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Asked On
2005-03-27 at 18:32:45ID21366414
Tags

two

,

strings

,

compare

Topic

Active Server Pages (ASP)

Participating Experts
3
Points
500
Comments
6

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Answers

 

by: alorentzPosted on 2005-03-27 at 18:40:48ID: 13641464

Do this:

<%
response.write "realname = <br>|" & DecodedName & "|<br>"
response.write "couponother = <br>|" & Realname & "|<br>
%>

I'm guessing there's some blank spaces in there

 

by: alorentzPosted on 2005-03-27 at 18:41:38ID: 13641468

Also try this:

<%
if ucase(trim(DecodedName)) <> ucase(trim(Realname)) then
     msg= "Bad coupon name"
     rc=4
     exit sub
end if
%>

 

by: alorentzPosted on 2005-03-27 at 18:51:31ID: 13641508

Could also do this:

<%
if ucase(left(DecodedName, len(realname))) <> ucase(Realname) then
     msg= "Bad coupon name"
     rc=4
     exit sub
end if
%>

Maybe return carriage or line feed on end of decode name, so just take the length of the realname and compare.

 

by: calvinfooPosted on 2005-03-27 at 19:47:19ID: 13641674

Hi,

 try this:

  if ucase(trim(DecodedName)) <> ucase(trim(Realname)) then
     msg= "Bad coupon name"
     rc=4
     exit sub
end if

 

by: calvinfooPosted on 2005-03-27 at 19:48:17ID: 13641679

ops, sorry, I guess I've repeated what alorentz said.

 

by: Sukamal_SenguptaPosted on 2005-03-27 at 22:59:11ID: 13642115

Hi humer2000,

Hope the string that you get after decrypte the string (which is store in the db) is done correctly means there is no any hidden word or space included into that string, which is not shown in the browser.
 
Try the following code which is slightly modified from your code,

Sub ValidateCoupon (rc, msg)
    dim EncodedName, DecodedName, Realname
    EncodedName=couponname
    DecodedName= Base64decode(EncodedName)
    Realname = couponother

   DecodedName = Trim(cstr(DecodedName))
   Realname = Trim(cstr(Realname ))

   response.write "DecodedName = <br>" & DecodedName & "<br>"
   response.write "Realname = <br>" & Realname

  if ((cstr(DecodedName)) <>(cstr(Realname))) then
     msg= "Bad coupon name"
     rc=4
     exit sub
  end if

end sub


Hope you don't use the procedure i.e., ValidateCoupon within any loop.

Try the Modified code. Hope your problem will be solved.

Thanks,
Sukamal Sengupta


 

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