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Understanding the DateDiff function
Does anyone know why the code below would return 5 or 6 for its value when LastContacted is 10/21/2009. I only want it to return 5 because there are 5 days in between today and that date.
Any direction you can provide would be appreciated.
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Answers
> Why those chars: "#
Because we want to convert the result of dateFormat to a literal string so that dateDiff doesn't view it as a data type date
In essence, we are passing the string "10/27/2009" to the function
> Andy why to format the date if it is already a date
I made the assumption that lastContactDate had a time element included in the date which was preventing a full 6 day difference between the two date values (for example it was 5 days and 20 hours)
I thought dateDiff('d', would handle this.. I guess I should just test it..
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by: onaled777Posted on 2009-10-26 at 14:10:25ID: 25666948
ok...I was made to understand that lastContactDate may be a timestamp so it tends to depend on the time the query is run. Exactly how do i get around this?