Question

Trying to get property of non-object in PHP Class

Asked by: msiedle

Hi all

I've turned on error notices and I'm getting one consistent problem throughout all my classes ...it doesn't like lines 17 and 18 where i use "$this" ...can anyone suggest what the problem is with my code? ...must work in both php4 and php5

The error is: "Trying to get property of non-object in line 17" ...

1      class Header_Image
2      {
3            //private variables
4            var $image_id = '';
5            var $filename = '';
6            
7            function select_Record($object) {
8                  $image_id = $object->image_id;
9
10                  $query = mysql_query("      SELECT *
11                                    FROM $DB.header_image
12                                    WHERE image_id = '$image_id'");
13                  errorcheck();
14
15                  $result = mysql_fetch_object($query);
16
17                  $this->image_id = $result->image_id;
18                  $this->filename = stripslashes($result->filename);
19            } //end function
20            //**************
...


Thanks
Mark

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Asked On
2005-12-22 at 22:50:09ID21674004
Tags

get

,

property

,

trying

Topic

PHP and Databases

Participating Experts
1
Points
250
Comments
3

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Answers

 

by: blue_hunterPosted on 2005-12-23 at 00:56:31ID: 15540592

15               $result = mysql_fetch_object($query);
16
17               $this->image_id = $result->image_id;

suggest to change to following



$result = mysql_fetch_array($query);
 $this->image_id = $result["image_id"];



cheers


 

by: msiedlePosted on 2005-12-23 at 04:28:41ID: 15541584

Thanks ...no more error notice

Could I ask why mysql_fetch_array works instead of mysql_fetch_object? I thought they worked the same way except one creates an object, while the other creates an array?

Cheers,
Mark

 

by: blue_hunterPosted on 2005-12-23 at 04:58:15ID: 15541815

probably you have more than 1 records selected out from DB

so, if insisting using the mysql_fetch_object($query), please do so :

while ($row = mysql_fetch_object($query)) {
   echo $row->user_id;
   echo $row->fullname;
}


mysql_fetch_array() returns an array that corresponds to the fetched row and moves the internal data pointer ahead.  ( From: php.net: http://my.php.net/manual/en/function.mysql-fetch-array.php)


*notes - for the mysql_fetch_array() each time only one record will be fetched.
so,

$result = mysql_fetch_array($query);  <----- this work for you; although more than 1 records is returned from the query

you might do some little bit testing on this.


regards.

20120131-EE-VQP-002

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