I am storing a bunch of articles in a folder called "articles" EACH article is on a php file EXAMPLE: "art_one.php"," art_two.php", etc....... I want to display one of those articles randomly on my index.php page everytime the page is loaded. How can I accomplish this.
Thanks
Phil
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If you wanted to display the contents on fhe article thats stored in another php file, you are going to have to include() it, and that only works well if theres only article text there and not a whole menu system or whatever.
I suggest you store the articles in MySQL and query the database directly instead of requiring another file to do it.
Thanks Bota can you go back and look at this question again
http://www.experts-exchang
If you don't want to use a database to store your article names, you could just use a script on your index.php file. BOTA-X has it with needing to use includes to get the article to display within your index.php page, but I would not create the array on my own as mgh_mgharish suggests. I would instead use a file listing function to return the array of articles.
Stolen from php.net's notes:
This code will go within your index.php page.
<?php
$BASEDIR="/tmp"; //CHANGE THIS TO BE THE DIRECTORY FROM YOUR SERVER'S ROOT TO THE ARTICLES DIRECTORY
function recursedir($BASEDIR) {
$hndl=opendir($BASEDIR);
while($file=readdir($hndl)
if ($file=='.' || $file=='..') continue;
$completepath="$BASEDIR/$f
if (is_dir($completepath)) {
# its a dir, recurse.
recursedir($BASEDIR.'/'.$f
} else {
# its a file.
$arr[] = $file;
}
}
}
recursedir($BASEDIR);
?>
You'd then need to include the random article from $arr
include($arr[rand(0,count(
Hope this helps.
Business Accounts
Answer for Membership
by: mgh_mgharishPosted on 2005-12-27 at 17:58:43ID: 15560089
Hi smphil,
<?php
$arr = array("one","two","three")
echo "art_" . $arr[rand(0,count($arr)-1)
?>
---
Harish